2*【x+(x+40)】=400
2*【x+(x+40)】=400
(x/x-1)+(5x-2)/x*x-x=1 求x(有图)
400=x^2+(x+x)^2
2x+(22-x)=40
(40-x)(20+2x)=1200 800+80X-20X-2x^2=1200 -2x^2+60X-400=0 x^2
(20-2x)(20-2x)x>400 x=?
f(x)=x²+3x|x-2|
f(x)=-x^2+2x(x>0) 0(x=0) x^2-2x(x
解方程(x-2)X(x的平方-6x-9)=x(x-5)X(x-3)
(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8
解方程:(x-8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)
(x)-2x·x-x-2x+1=0求x的值,