根据下列各组x、y的值,分别求出代数式x2+2xy+y2与x2-2xy+y2的值:(1)x=2,y=3; (2)x
根据下列各组x、y的值,分别求出代数式x2+2xy+y2与x2-2xy+y2的值:(1)x=2,y=3; (2)x
已知2x=3y,求xy/(x2+y2)-y2/(x2-y2)的值
已知X2+Y2+8X+6Y+25=0 求代数式X2++XY+4Y2分之X2-4Y2 减X+2Y分之X的值
已知:x=3,y=-5,x2-2xy+y2/x2-y2的值是
x(x-1)-(x2-y)=-3,求x2-y2-2xy的值
x(x-1)-(x2-y)=-3,求x2+y2-2xy的值
已知x(x-1)-(x2-y)=-3,求x2+y2-2xy的值
若X2+Y2-2X-6Y+10=0 ,求(x2-y2)/xy的值
已知x(x-1)+(y-x2)=6,则代数式x2+y2/2-xy的值是
已知x-y+1,X2+Y2=25 求(x+y)2和x2-xy+y2的值
正数xy满足x2-y2=2xy,求x+y分之x-y的值
已知x=y+4,求代数式x2-2xy+y2-25的值.