英语数学题要有解题方法!1.The sum of n different natural numbers is less
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英语数学题
要有解题方法!
1.The sum of n different natural numbers is less than50.the greatest possible value of n is----
2.Let a be the average of all odd prime numbers less than 50.The inreger,most close to a is----
3.If two even natural numbers x,y satisfy equation x的平方加100等于y的平方,x大于y then x乘y等于----
要有解题方法!
1.The sum of n different natural numbers is less than50.the greatest possible value of n is----
2.Let a be the average of all odd prime numbers less than 50.The inreger,most close to a is----
3.If two even natural numbers x,y satisfy equation x的平方加100等于y的平方,x大于y then x乘y等于----
1. Since there are some controversies, I suppose 0 does not belong to natural numbers in this case. The answer is quite straight foward, 1+2+3+4+5+6+7+8+9=45. If we add 10, then the sum will exceed 50. So the greatest possible n is 9.
2. First of all, you can list all the odd prime numbers less than 50:3 5 7 11 13 17 19 23 29 31 37 41 43 47. Add them up, and calculate the average. The average a is equal to 23.3. Therefore the integer, most close to a is 23.
3. x^2+100=y^2,then (y-x)(x+y)=100, since x and y are natural numbers, x+y>0, y should be larger than x. I am afraid there is either something wrong with the problem or a typing mistake.
You can show me the original version of the problem 3.
2. First of all, you can list all the odd prime numbers less than 50:3 5 7 11 13 17 19 23 29 31 37 41 43 47. Add them up, and calculate the average. The average a is equal to 23.3. Therefore the integer, most close to a is 23.
3. x^2+100=y^2,then (y-x)(x+y)=100, since x and y are natural numbers, x+y>0, y should be larger than x. I am afraid there is either something wrong with the problem or a typing mistake.
You can show me the original version of the problem 3.
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