用MATLAB画图,例>> x=0:pi/15:2*pi; >> y1=sin(x); >> y2=cos(x); >>
用MATLAB画图,例>> x=0:pi/15:2*pi; >> y1=sin(x); >> y2=cos(x); >>
matlab基础 x=0:0.1:2*pi;y1=sin(x);y2=cos(x);z=[y1,y2];plot(x,z
matlab中如何画图!x=-pi:0.1:pi; y=cos(x)/cos(2*x);plot(x.y)
Matlab u(x,t)=sin(5*pi*x)cos(5*pi*t)+2sin(7*pi*x)cos(7*pi*t)
用MATLAB编写代码:画y1=sin(2x)和y2=cos(2x)在区间[0,4*pi]的曲线,用+标出两条曲线的交点
用MATLAB编写代码:绘制y1=sin(2x)和y2=cos(2x)在区间[0,4*pi]的曲线,用加号标出两条曲线的
matlab中 x=[0:0.15:2*pi]; y=[0:0.15:2*pi]; z=sin(y‘)*cos(x);
程序如下:x=linspace(0,4*pi,100);y1=sin(x);y2=cos(x);y3=sin(x)./(
matlab二维绘图x=0:0.1*pi:4*pi;y=sin(x);z=cos(x);v=[0,15,-2,2];ax
matlab中y=(0.5+3.*sin(x*pi/180)./(1+x^2)).*cos(x*pi/180);哪里错了
已知函数f(x)=cos(2x-pi/3)+2sin(x-pi)*sin(x+pi/4)
x=-pi:0.1:pi; fh={@cos,@sin}; plot(fh{2}(x)) 刚学习matlab,谁帮我解释