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求解(1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.12+0.

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/18 10:35:50
求解(1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.12+0.23)=?
(1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.12+0.23)
=(1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23)*(0.12+0.23)-0.34*(0.12+0.23)
=(1+0.12+0.23)*[(0.12+0.23+0.34)-(0.12+0.23)]-0.34*(0.12+0.23)
=(1+0.12+0.23)*0.34-0.34*(0.12+0.23)
=[(1+0.12+0.23)--(0.12+0.23)]*0.34
=1*0.34
=0.34
再问: 为什么要这样啊
再答: 你不想这样也行呀 (1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.12+0.23) =1.35*0.69-1.69*0.35 =0.9315-0.5915 =0.34