log底2(X) + log底2(5)=4
log底2(X) + log底2(5)=4
已知log(2)[log(3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x
log(x+5)=log(x)+log(2) log(8)+log(x)=log(24) 2log(x)=log(2x)
log的数学题2 + log 2(为底)4= 3x-1
利用对数的换底公式化简下列 1.log(a)c×log(c)a 2.log(2)3×log(3)4×log(4)5×lo
log以2为底的(log以3为底的(log以4为底的x))=log以3为底的(log以4为底的(log以2为底的y))=
对数计算1.{log(4)(3)+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log(
log(X+5)+log(X+2)=1
1/log(2)x+1/log(3)x+1/log(4)x=1,x=?
log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4)
[( log(x^2) + log(x^4) )/ log(100 x)] = 4 求X
2log底3x+log底3 2=1/2log底3 16 x为什么值