MATLAB z=100000*sin(y*pi/180)/(17*sqrt(3+sin(2*x*pi/180)));是
MATLAB z=100000*sin(y*pi/180)/(17*sqrt(3+sin(2*x*pi/180)));是
matlab中 x=[0:0.15:2*pi]; y=[0:0.15:2*pi]; z=sin(y‘)*cos(x);
matlab中y=(0.5+3.*sin(x*pi/180)./(1+x^2)).*cos(x*pi/180);哪里错了
y=sin(x+pi/3)sin(x+pi/2)的最小正周期是什么
matlab二维绘图x=0:0.1*pi:4*pi;y=sin(x);z=cos(x);v=[0,15,-2,2];ax
用matlab解方程:11169.66-5662.65*(sin(x-93*pi/180)+sin(93*pi/180-
matlab中问题:x = A1 * sin(2 * pi * f1 * t) + A2 * sin(2 * pi *
Matlab的作图命令,x = 0:pi/100:2*pi; y = sin(x); plot(x,y)
matlab 三角函数 y=sin(x) x=0:pi/50:pi 积分后 作图
y=sin(2x+Pi/3)+cos(Pi/6-2x)周期为
y=sinxy=2sin(x/3+pi/6)
已知cos(x)=sqrt(10)/10,x属于(0,pi/2),求sin(pi/4+2x)的值