(1-x/3-x)²/(3-2x-x²/9-x²)³*(x²/x

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/14 04:22:14

(1-x/3-x)²/(3-2x-x²/9-x²)³*(x²/x²-2x-3)
过程一定要有

原式
=(1-x/3-x)²/(3-2x-x²/9-x²)³*(x²/x²-2x-3)
=(x-1)²/(x-3)² × (x+3)³(x-3)³/(x-1)³(x+3)³ × x²/(x+1)(x-3)
= 1/(x-1)× x²/(x+1)
=x²/(x+1)(x-1)
=x²/(x²-1)

（2x²-2x+3)(-x³+x-1) x²+3x+9/(x²-27)+6x/(9x-x²)-(x-1)/(6+2x) (1-x/3-x)²/(3-2x-x²/9-x²)³*(x²/x 1.(x²-9)/(x²+2x²+x)*(3x³+9x²)/(x 4x²-1/3x²-x·9x³-x/2x^4-x³计算急 (x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3 6x+(2x²-3x)-(x²-1) (x+1)/(x²+3x+2)+(x²-2x)/(x²-4) x(x²-1)+2x²（x+1)-3x（2x-5)计算 ①2(x+3)(x-3)=x²+(x-1)(x+1)+2x (x-1)(2x²-3x+2)-x(x+1)(x-2) 3x³-2x*x²