1949×(1/51-1/2000)+51×(1949-1/2000)-2000×(1/1949+1/51)+3
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1949×(1/51-1/2000)+51×(1949-1/2000)-2000×(1/1949+1/51)+3
1949*(1/51-1/2000)+51*(1/1949-1/2000)-2000*(1/1949+1/51)+3
=1949/51-1949/2000+51/1949-51/2000-2000/1949-2000/51
=(1949/51-2000/51)+(51/1949-2000/1949)-(1919/2000+51/1949)+3
=-51/51-1949/1949-2000/2000+3
=-1-1-1+3
=0
=1949/51-1949/2000+51/1949-51/2000-2000/1949-2000/51
=(1949/51-2000/51)+(51/1949-2000/1949)-(1919/2000+51/1949)+3
=-51/51-1949/1949-2000/2000+3
=-1-1-1+3
=0
1949×(1/51-1/2000)+51×(1949-1/2000)-2000×(1/1949+1/51)+3
1949*(1/50-1/2000)+51*(1/1949-1/2000)-2000*(1/1949+1/51)+3
1949x(1/51-1/2000)+51x(1/1949-1/2000)-2000X(1/1949+1/51)+3
1949*(1/51-1/2000)+51*(1/1949-1/2000)-2000*(1/1949+1/51)
1949*(1/51-1/2000)+51*(1/1949-1/2000)=2000*(1/51-1/1949)
1949*(1/51-1/2000)+51*(1/1949-1/2000)+3
1949x(1/51—1/2000)+51X(1/1949—1/2000)—2000X(1/1949+1/51)+3的计
(1-1∕2)+(1∕2-1∕3)+(1∕3-1∕4)+…+(1∕1999+1∕2000)
1-2+3.+1999-2000+2001-2002的结果是几?( 要用拖试计算 )
已知X²-5X-2000=0,求(X-2)³-(X-1)²+1/X-2的值
1、1949*2003+1952*2000+1955*1997+...+2003*1949=?
cosα=1/17,cos(α+β)=-47/51,且0