2x+3y/2+3x+2y/5=11/3,3(2x+3y)/2=6(3x+2y)/7+2.5,求教啊= =
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2x+3y/2+3x+2y/5=11/3,3(2x+3y)/2=6(3x+2y)/7+2.5,求教啊= =
2x+3y/2+3x+2y/5=11/3 ,3(2x+3y)/2=6(3x+2y)/7+2.5
2x+3y/2+3x+2y/5=11/3 ,3(2x+3y)/2=6(3x+2y)/7+2.5
题目中第一式是不是应该是:(2x+3y)/2+(3x+2y)/5=11/3 , 否则这样出没意义.
如果是这样的话,解法如下:
15(2x+3y)+6(3x+2y)=110, 21(2x+3y)-12(3x+2y)=35
48x+57y=110,6x+39y=35
加减法解得:x=3/2, y=2/3
再问: 好吧,我知道等于48x+57y=110,6x+39y=35。然后下面的我就算不出来,算了好几次= =
再答: 1) 48x+57y=110, 2)48x+312y=280, 2)-1)得255y=170,所以y=2/3,代入6x+39y=35就可以解得x=3/2
如果是这样的话,解法如下:
15(2x+3y)+6(3x+2y)=110, 21(2x+3y)-12(3x+2y)=35
48x+57y=110,6x+39y=35
加减法解得:x=3/2, y=2/3
再问: 好吧,我知道等于48x+57y=110,6x+39y=35。然后下面的我就算不出来,算了好几次= =
再答: 1) 48x+57y=110, 2)48x+312y=280, 2)-1)得255y=170,所以y=2/3,代入6x+39y=35就可以解得x=3/2
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2x+3y/2+3x+2y/5=11/3,3(2x+3y)/2=6(3x+2y)/7+2.5,求教啊= =
x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20
{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20
4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1