n趋向正无穷时,[(2n-1)!/(2n!)]的极限是多少?
n趋向正无穷时,[(2n-1)!/(2n!)]的极限是多少?
n次根号[1+x^(2n)]的极限(n趋向正无穷)
n趋向正无穷 求极限n*[e^2-(1+1/n)^2n]
求极限:Lim(1+1/n-1/n^2)^n n趋向于正无穷
n(1-2的n分之a次方) 当n趋向无穷 极限是多少
求n趋向无穷时 [(1+1/n)(1+2/n)...(1+n/n)]^1/n 的极限?
计算数列极限,当N趋向于无穷时,根号下(N^2+4N+5)-(N-1)的极限
(2+(2/3)^1/n)^n,求当n趋向于正无穷的极限
证明n趋向无穷时,5n^2/(7n-n^2)的极限等于-5
Γ[(n+1)/2]/ Γ(n/2) n趋向于无穷,的极限是多少 怎么算的
极限n趋向正无穷,求解定积分,lim(n趋向于无穷)定积分(0到1)x∧n/1+x∧2n
用数列极限的定义证明:lim(3n+1)/(2n+1)=3/2 ,当n 趋向于正无穷时.