y=2sin(x 2 pai 3) 可以得到 y=sinx

y=sinx的图像横坐标不变,纵坐标变为原来的2倍得y=2sinx的图像y=2sinx的图像纵坐标不变,横坐标变为原来的1/2倍得y=2sin2x的图像y=2sin2x的图像向左平移|π/6|得y=2

(1)振幅为1,周期为2π/2=π,初相位为π/3(2)可由y=sinx先横坐标变为原来的2倍,然后左移π/6

向右移π/3个单位y=sin(2x-π/6)=sin（π/2+2x-π/6-π/2）=sin（π/2+2x-2π/3）=sinπ/2*cos（2x-2π/3）+cosπ/2*sin（2x-2π/3）=

y'=f'(sin²x)*(sin²x)'+f'(cos²x)*(cos²x)'=f'(sin²x)*(2sinxcos)+f'(cos²x

y=sinx;x→x-π/6(即右移π/6个单位)得y=sin(x-π/6);x→2x(即每点横坐标缩短为原来的1/2)得y=sin(2x-π/6)；再将纵坐标拉伸为原来的2倍得y=2sin(2x-π

把y=sinx的图像向左平移π/6个单位,得y=sin(x+π/6)的图像,再把各点的纵坐标不变,横坐标变为原来的2倍,得y=sin(x/2+π/6)的图像,然后把各点的横坐标不变,纵坐标变为3倍,得

第一步：y=sinx向左平移π个单位得到y=sin(x+π)[平移变换]第二步：y=sin(x+π)纵坐标不变横坐标变为原来的1/2倍得到y=sin(2x+π)【横向伸缩变换】第三步：y=sin(2x

y=sinx先向左平移π/4个单位,然后横坐标缩小2倍

d/dx(f(sin^2(x))+sin(f(x)^2)) = sin(2 x) f'(sin^2(x))+2 f(x) f'

y=1+sin2x+2cos²x-1=sin2x+cos2x+1=√2sin[2(x+π/8)]+1所以是向左π/8,横坐标变成原来的1/2纵坐标变成原来的√2倍再向上1个单位

y=2sin(2x-π/3)=2sin2(x-π/6)所以,是由y=2sin2x向右平移π/6个单位

左边=(sinxcosy+cosxsiny)(sinxcosy-cosxsiny)=sin²xcos²y-cos²xsin²y=sin²x(1-sin

f(x)=sin^2x-2sinxcosx+3cos^2x=1/2（1-cos2x）-sin2x+3/2（1+cos2x）=2+cos2x-sin2x=2+√2cos（2x+π/4）y=cos2x先沿

dy/dx相当于对x进行求导：dy/dx=y'=2x*cos[sin(x^2)]*cos(x^2)由于：sinx=cosx,sin(x^2)=2x*cos(x^2)

看清楚题目!是y=sin(x/2+π/3)变成y=sinx/2不是y=sinx/2变成y=sin(x/2+π/3)!orz我和我同桌也犯了同样的错误,这题的题目...唉

sinx+siny+sinz-sin(x+y+z)=4sin[(x+y)/2]sin[(x+z)/2]sin[(y+z)/2]sinx+siny+sinz-sin(x+y+z)=2sin[(x+y)/

直线ρsin(θ+π4)=22，可化为x+y-1=0，点A(2，7π4)可化为A(2，-2)，根据点到直线的距离公式d=|2-2-1|2=22，故答案为22．

若看不清楚,可点击放大.

y=sin(2x+π/6)=cos[π/2-(2x+π/6)]=cos(-2x+π/3)=cos(2x-π/3)=cos[2(x-π/6)]左加右减所以向右移π/6

y'=f'(sin(2x))*(sin(2x))'+(sin(f(2x)))'*f'(2x)=f'(sin(2x))*2*cos(2x)+cos(f(2