y(1 x^2-y^2)^(1 2)dy
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原式=x^2-xy-2xy-2y^2=2x^2-3xy-2y^22、是的,你算错了,以后要细心!原式=(a^2+4ab+4b^2)(2a+b^2)=2a^3+a^2b^2+8a^2b+4ab^3+8a
1、4(x-y+1)+y(y-2x)=4x-4y+4+y²-2xy=y²-4y+4-2xy+4x=(y-2)²-2x(y-2)=(y-2x-2)(y-2)2、4x^4-1
(x+2)(x+3)=x²+5x+6(x-4)(x+1)=x²-3x-4(y+4)(y-2)=y²+2y-8(y-5)(y-3)=y²-8y+15x²
原式=(9x^2-3xy+1/4y^2+3xy-1/4y^2)÷(4x^2+4xy+u^2-4xy-y^2)=9x^2÷4x^2=9/4
1)x(x-y)(x+y)-x(x+y)^2=x((x-y)(x+y)-(x+y)^2)=x(x^2-y^2-x^2-2xy-y^2)=x(-2xy-2y^2)=-2xy(x+y)2)(2a+b)(2
[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y=[x²-y²-x²-2xy-y²-xy+xy²]/(y/2)=[(x-2)y
.死算呗xy-2x+3y-6=xy+10x-3y-30,2x-y=4xy+3x+y+3=xy+12x-2y-24,3x-y=92式减1式,x=5,y=6
4(x-y+1)+y(y-2x)=4x-4y+4+y^2-2xy=(y^2-4y+4)-2x(2-y)=(y-2)^2+2x(y-2)=(y-2)(2x+y-2)
1)4xy2)-1/5y^23)2ab^2c4)(2a+b)^25)2yz+xz6)-3a-57)4xy
4(x-y+1)+y(y-2x)=4x-4y+4+y^2-2xy=(2-y)^2+2x(2-y)=(2-y)(2-y+2x)4x^4-13x²+9=4x^4-12x^2+9-x^2=(2x^
原式=(9x^2-3xy+1/4y^2+3xy-1/4y^2)÷(4x^2+4xy+u^2-4xy-y^2)=9x^2÷4x^2=9/4
1)(2x+5y)(2x-5y)(-4x^2-25y^2)=-(4x^2-25y^2)(4x^2+25y^2)=-(16x^4-625y^4)=625y^4-16x^42)[(x+y)(x-y)-(x
(1)x^2/x)-y-x-y=x-y-x-y=-2y(2)(a/a-b)-(a/a+b)-(2b^2/a^2-b^2)=a(a+b-a+b)/(a^2-b^2)-(2b^2/a^2-b^2)=2b/
解(x-y)(x+y)-(x-2y)²+x(3x-5y)-(x-y)(x-2y)=(x²-y²)-(x²-4xy+4y²)+(3x²-5xy
(x-y)^2+12(x-y)+36=(x-y+6)²;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,再问:Guoc过程再答:(x-y)^2+12(x-y
4x=9yx=9/4*y(1)(x+y)/y=[(9/4)y+y]/y=(9/4+1)y/y=9/4+1=13/4(2)(y-x)/2x=[y-(9/4)y]/[2*(9/4)y]=(1-9/4)y/
(x+y)-(2x+1/2y)-(3x+1/6y)-(4x+1/12y)-(5x+1/20y)-.-(10x+1/90y)=x+y-2x-1/2y--3x-1/6y-4x-1/12y-5x-1/20y