X的平方减Y的平方分之Y减X约分等于多少
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原式=(X的平方+Y)*(X的平方-Y)/(X+Y)*(X-Y)如果,是Y的四次方就好求了
通分为分母是(x+y)⒉(x-y),即为2xy(x-y)/(x+y)⒉(x-y)和x(x+y)/(x+y)⒉(x-y)
前者分子:x^2-y^2=(x+y)(x-y)那前面这项就可以化简约分啦后者分子:4x^2-4xy+y^2=(2x)^2-2*2xy+y^2=(2x-y)^2建议你理解一下x^2-2xy+y^=(x-
x^2+y^2-6x-8y+25=0变为:(x^2-6y+9)+(y^2-8y+16)=0(x-3)^2+(y-4)^2=0即:(x-3)^2=0,且(y-4)^2=0所以:x=3,y=4因此:y/x
x/y=2所以x=2y所以xy=2y²x²=4y²(x²-xy+3y²)/(x²+xy+6y²)=(4y²-2y&sup
[(x²+y²-9)²-4x²y²]/(x²+6x+9-y²)=(x²+2xy+y²-9)(x²-2
如果问题写清楚一些就好啦
3∵x/y=1/2∴y=2x故(x^2+2xy+y^2)/(x^2-xy+y^2)=(x+y)^2/(x^2-xy+y^2)=(x+2x)^2/(x^2-x·2x+4x^2)=9x^2/(3x^2)=
解题思路:把分式的分子分母分解因式再根据法则进行计算,能约分的要先约分解题过程:答案见附件
x^2+y^2-10x-12y+61=(x-5)^2+(y-6)^2=0,——》x=5,y=6,——》x/y-y/x=5/6-6/5=-11/30.
拍张图片再问:再答:再答:有数学题可以求助我
原式=[(x+y)/(x-y)]^2*[2(x-y)/5(x+y)-[X/(x^2y^2)]/[x/(x+y)]=2/5-[x/(x^2y^2)]*[(X+y)/x]=2/5-(x^2y^2)/(x+
(x^2+y^2)^2-4x^2y^2=(x^2+y^2+2xy)(x^2+y^2-2xy)=(x+y)^2*(x-y)^2=(x^2-y^2)^2数学佰亊嗵为你解答,希望我的回答为您带来帮助!
[x²-(y-z)²]/[(x+y)²-z²]=(x+y-z)(x-y+z)/(x+y+z)(x+y-z)=(x-y+z)/(x+y+z)再问:谢谢你!但是最终
(x+y)²(x-y)-(x+y)(x²+y²)=(x+y)[(x-y)(x+y)-(x²+y²)]=(x+y)(x²-y²-x&
(1-y+x分之y)÷y的平方-x的平方分之x=[(y+x-y)/(y+x)]÷x/(y²-x²)=x/(y+x)*[(y+x)(y-x)/x]=y-x
原式=(X-Y)²/(X+Y)(X-Y)=(X-Y)/(X+Y)=(√3+1-√3+1)/(√3+1+√3-1)=2/2√3=1/√3=√3/3
解x-3y=0x=3y(4xy)/(x²-y²)-(x+y)/(x-y)=(4xy)/(x+y)(x-y)-(x+y)²/(x-y)(x+y)=(4xy-x²-