x的平方-2 x分之1-x除以(x-2 x 2分之3),其中x等于2分之1
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(1-x)^2/(x^2+4x+4)/(x-1)^2*(x^2+3x+2)/(x-1)=(x+1)/(x+2)(x-1)=(x+1)/(x^2+x-2)再问:是1-x的平方,不是(1-x)的平方再答:
原式=[(x-1)/(x²-x-2)]²÷[(x²-2x+1)/(2-x)]÷[1/(x²+x)]²=[(x-1)²/(x²-x-
[x的平方-x分之x+1-x的平方-2x+1分之x]除以x分之1=[(x+1)/x(x-1)-x/(x-1)²]×x=(x+1)/(x-1)-x²/(x-1)²=(x
〔(x-1)/(x+2)〕×〔(x^2-4)/(x^2-2x+1)〕÷(1/x^2)=〔(x-1)/(x+2)〕×〔(x+2)(x-2)/(x-1)^2〕×x^2=〔(x^2)(x-1)(x+2)(x
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再答:望采纳,谢谢
原式=[1/x(x-2)-1/(x-2)²]*x²/2=[(x-2-x)/x(x-2²]*x²/2=-2/x(x-2)²*x²/2=-x/(
x的平方-2x+1分之x²-1+x-2分之2x-x²除以x=(x+1)(x-1)/(x-1)²-x(x-2)/(x-2)÷x=(x+1)/(x-1)-1=(x+1-x+1
x的平方-4分之x+1*(x+2)-x的平方+8x+16分之x的平方-16除以(x-4)=x的平方-四分之x+x+2-x的平方+8x+十六分之x的平方-(x-4分之16)=(x的平方-x的平方+十六分
[x的平方-x分之x+1-x的平方-2x+1分之x]除以x分之1=[(x+1)/x(x-1)-x/(x-1)²]×x=(x+1)/(x-1)-x²/(x-1)²=(x
先化简,然后代入求值就可以了再问:好吧。。。已经做完了
)【(x²-2x+1)/(x²-1)】÷【(x-1)/(x²+x)】=【(x-1)²/(x+1)(x-1)】÷【(x-1)/x(x+1)】=【(x-1)/(x+
=[(x+1)(x-1)/(x-1)²-(x-1)/(x+1)]×(x-1)/x=[(x+1)²-(x-1)²]/(x+1)(x-1)×(x-1)/x=4x/(x+1)(
(x的平方-1)分之(x的平方-2x+1)除以(x的平方+x)分之(x-1)-x=[(x+1)(x-1)]分之(x-1)²÷[x(x+1)]分之(x-1)-x=(x+1)分之(x-1)×[(
[(x-1)/x-(x-2)/(x+1)]÷[(2x^2-x)/(x^2+2x+1)]=[(x-1)(x+1)-x(x-2)]/x(x+1)÷[x(2x-1)/(x+1)^2=(2x-1)/x(x+1
(x的平方-1分之x的平方-2x+1+x分之1)除以x+1分之1=((x-1)^2/(x-1)(x+1)+1/x)*(x+1)=((x-1)/(x+1)+1/x)*(x+1)=(x-1)+(x+1)/
(x²-6x+9)/(x+1)÷(x²-9)/(x²+x)=[(x-3)²/(x+1)]×[x(x+1)/(x+3)(x-3)]=x(x-3)/(x+3)x的平
2x分之x的平方-4x+4除以x平方分之x的平方-2x+1等于2分之x,当x=0或2时,分式无意义
[(x²-4x+4)/(2x)]÷[(x²-2x+1)/x²]=[(x-2)²/(2x)]/[(x-1)²/x²]=(x-2)²x
x的平方-1分之x除以x的平方分之x的平方=x²-(x/1)/(x²/x²)=x²-(x)/1=x²-x