x²-xy+四分之一y²的因式分解-搜答案-智慧作业帮

1/4x²y²-xy³+y⁴=y²(1/3x²-xy+y²)=y²[(1/2x)²-2×(1/2x)y+y&

（x-y）（x-y-2）-3

答：-x³y+2x²y-xy=-xy(x²-2x+1)=-xy(x-1)²

3x(x^2-2)y^2+6xy^2+9x^2y^2再问：O(∩_∩)O谢谢再答：原式=3x^3-6x^2y+3xy^2提取公因式，得3x(x^2-2xy+y^2)由完全平方公式，得3x(x-y)^2

原式=-y(4x²-4xy+y²)=-y(2x-y)²

6xy^2-9x^2y-y^3=-y(-6xy+9x^2+y^2)=-y(9x^2-6xy+y^2)=-y(3x-y)^2

xy(x-y)-x(x-y)平方=(x-y)[xy-x(x-y)]=(x-y)[2xy-x^2]=(x-y)*x(2x-y)-a平方+1.9b平方=(b根号1.9+a)(b根号1.9-a)-12xy+

2.6x²-13xy+6y²+22x-23y+20=(2x-3y)(3x-2y)+22x-23y+4×5=(2x-3y+4)(3x-2y+5)3.(x²+4x+8)

4xy的平方-4x的平方y-y的三次方=y(4xy-4x^2-y^2)=-y(4x^2-4xy+y^2)=-y(2x-y)^2

双十字相乘.

由x³-2x²y+xy²-x=x（x²-2xy+y²-1)=x[（x-y）²-1]=x（x-y-1）（x-y+1）.再问：分解因式：-49x

1x²+2xy-3y²=x²+2xy+y²-4y²=（x+y）²-(2y)²=(x+y+2y)(x+y-2y)=(x+3y)(x-

xy²－2xy＋2y－4原式＝xy（y－2）＋2（y－2）＝（xy＋2）（y－2）

设t=xy+1;(xy+1)(x+1)(y+1)+xy=t(x+1)(y+1)+xy=t(xy+x+y+1)+xy=t(t+x+y)+xy=t^2+xt+yt+xy=(t+x)(t+y)-xy+xy=

xy^3-2x^2y^2+x^3y=xy(y^2-2xy+x^2)=xy(y-x)^2选我啊

用反证法.假设此多项式能够分解成两个一次因式的积.设x^2-xy+y^2+x+y=(x+ay+b)(x+cy+d)x^2-xy+y^2+x+y=(x+ay+b)(x+y+d)=x^2+(b+d)x+(

原式=(x+y)(x+2y)+2(x+2y)=(x+2y)(x+y+2)希望我的回答能帮助到您,

x^2-xy+y^2 分解因式

你的式子是无法分解的,已经是最简代数式了x^2-xy+y^2=（x-y/2）^2+3y^2/4恒大于0,无法分解

(1)3x²-4xy+6y²Δ=4²-4×3×6=16-72

(xy-1)^2+(x+y-2xy)(x+y-2)=(xy-1)^2+4xy+(x+y)^2-2(xy+1)(x+y)=(xy+1)^2+(x+y)^2-2(xy+1)(x+y)=(x+1)^2(y+