x²-2x除以2y-xy因式
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/25 21:12:05
先把括号化简去掉,注意去扩前的加减号,加号去括号不变号,减号去括号要变号,8(x^2-2y^2)-x(7x+y)+xy=8X^2-16y^2-7x^2-xy+xy排列一下化简后因式的顺序,8x^2-7
(xy-1)^2+(x+y-2)(x+y-2xy)=(xy-1)^2+(x+y)^2-2(xy+1)(x+y)+4xy=(xy+1)^2+(x+y)^2-2(xy+1)(x+y)=[(xy+1)-(x
(1-x^2)(1-y^2)+4xy=1-x²-y²+x²y²+4xy=(x²y²+2xy+1)-(x²-2xy+y²)
壹点丶dream:-2xy-x²-y²=-(2xy+x²+y²)=-(x+y)²
2xy+9-x^2-y^2=9-x^2-y^2+2xy=9-(x^2+y^2-2xy)=9-(x-y)^2=[3-(x-y)][3+(x-y)]=(3-x+y)(3+x-y)
解2x²y-x³-xy²=x(2xy-x²-y²)=-x(x²-2xy+y²)=-x(x-y)²
12x^2+xy-6y^2=(4x+3y)(3x-2y)
令x+y=a,xy=b原式化为:(b-1)^2+(a-2)(a-2b)=b^2-2b+1+a^2-2a-2ab+4b=b^2+2b+1+a^2-2a-2ab=(a^2-2ab+b^2)+2(b-a)+
你第一个是不是写错了?[2][(x-1)(y-1)]^2[3](x^3-x+1)(x^2+x+1)
8(x^2-2y^2)-x(7x+y)+xy=8x^2-16y^2-7x^2-xy+xy=x^2-16y^2=(x-4y)(x+4y)
是不是x^3y+x^2y+2xy^2-4xy^3原式=xy(x^2-4y^2)+x^2y+2xy^2=xy(x+2y)(x-2y)+xy(x+2y)=xy(x+2y)(x-2y+1)
=(x²-2xy+y²)²=(x-y)的4次方
这个题目看结构,应该是出错了,好像应该是(x^2-2xy)^2+2y^2(x^2-2xy)+y^4只有这样,才能形成完全平方公式(x^2-2xy)^2+2y^2(x^2-2xy)+y^4=(x^2-2
x²+2xy+y²-1=(x+y)²-1=(x+y+1)(x+y-1)
你的式子是无法分解的,已经是最简代数式了x^2-xy+y^2=(x-y/2)^2+3y^2/4恒大于0,无法分解
9-x^2+2xy-y^2=9-(x-y)^2=[3-(x-y)][3+(x-y)]=(3-x+y)(3+x-y)
原式=(x+y)(x+y)+2(x+y)xy+(xy)^2-1^2=(x+y)^2+2(x+y)xy+(xy)^2-1=(x+y+xy)^2-1=(x+y+xy-1)(x+y+xy+1)=(x+y+x
x^2-2xy+y^2-9=(x-y)^2-9=(x-y+3)(x-y-3)
(xy-1)^2+(x+y-2xy)(x+y-2)=(xy-1)^2+4xy+(x+y)^2-2(xy+1)(x+y)=(xy+1)^2+(x+y)^2-2(xy+1)(x+y)=(x+1)^2(y+