x² xy-2y² 2x 5y-3=

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已知X+Y=3XY,求2X+2Y-XY除以X+Y+2XY的值,要算理.

由X+Y=3XY可得X+Y-XY=2XY,用X+Y-XY替换分母中的2XY,所以(2X+2Y-XY)/(X+Y+2XY)=(2X+2Y-XY)/(2X+2Y-XY)=1

若x+y为有理数,且|x+1|+(2x-y+4)2=0,则代数式x5y+xy5=______.

根据题意得,x+1=0,2x-y+4=0,解得x=-1,y=2,∴x5y+xy5=(-1)5×2+(-1)×25=-2-32=-34.故答案为:-34.

已知x-y=4xy,求x-2xy-y分之2x+3xy-2y的值!

因为x-y=4xy所以x-2xy-y=2xy2x+3xy-2y=11xyx-2xy-y分之2x+3xy-2y=5.5

(-3x^y+2xy)-( )=4x^+xy

(-3x^y+2xy)-(4x^+xy)=-3x^y+2xy-4x^-xy=-3x^y+xy-4x^所以填上-3x^y+xy-4x^

已知x+y=3xy,求2x+2y-xy/x+y+2xy的值、

x+y=3xy,所以2x+2y-xy/x+y+2xy=(2×3xy-xy)/(3xy+2xy)=5/5=1

已知x+y分之xy=2,那么3x-5xy+3y分之3xy-x-y=

xy/(x+y)=2∴xy=2(x+y)(3xy-x-y)/(3x-5xy+3y)=[6(x+y)-x-y]/[3x+3y-10(x+y)]=5(x+y)/[-7(x+y)]=-5/7

已知xy/x+y =3,求2x-3xy+2y/-x+3xy-y 的值.

因为xy/x+y=3,所以xy=3(x+y)(1)将式子(1)代入求值式子:2x-3xy+2y/-x+3xy-y=2x-9x-9y+2y/-x+9x+9y-y=-7x-7y/8x+8y=-7/8

已知3/(x-y)=1/xy 求(-x-2xy+y)/ (2x+3xy-2y)

3/(x-y)=1/xyx-y=3xyy-z=-3xy原式=[(y-x)-2xy]/[2(x-y)+3xy]=[(-3xy)-2xy]/[2(3xy)+3xy]=-5xy/9xy=-5/9

由已知x+y=-2,xy=3那么2(x+xy)-[(xy-3y)-x]-(-xy)等于多少?

2(x+xy)-[(xy-3y)-x]-(-xy)=2x+2xy-xy+3y+x+xy=3x+3y+2xy=3(x+y)+2xy=3*(-2)+2*3=0

(x+2y-3xy)-(-2x-y+xy),其中x+y=1/2,xy=-1/2

(x+2y-3xy)-(-2x-y+xy)=x+2y-3xy+2x+y-xy=(1+2)x+(2+1)y-(3+1)xy=3x+3y-4xy=3(x+y)-4xy=3*1/2-4*(-1/2)=3/2

若(y-x)/xy=3,求分式(2x+3xy-2y)/(x-2xy-y)的值

3/5再问:详细过程呢再答:y-x=3xyx-y=-3xy代入得:(-6xy+3xy)/(-3xy-2xy)=-3/-5=3/5

已知x-y=4xy,则2x+3xy-2yx-2xy-y

∵x-y=4xy,∴2x+3xy-2yx-2xy-y=2(x-y)+3xyx-y-2xy=8xy+3xy4xy-2xy=112.故答案为:112.

已知xy/x+y=3,求2x-3xy+2y/-x+3xy-y的值

xy/x+y=3即:xy=3(x+y)(2x-3xy+2y)/(-x+3xy-y)=[2(x+y)-3xy]/[3xy-(x+y)]=[2(x+y)-9(x+y)]/[9(x+y)-(x+y)]=-7

(x+2y-3xy)-(-2x-y+xy),其中x+y=,xy=-,求值.

3x-4xy+3y再问:然后的过程再答:再带入值等于3.5再答:马上再答:给你照片再答:再答:亲采纳哟

已知x5y ……(1) 两边都减5,得0>5y-5x……(2) 即

错在第(4)步.∵x>y,∴y-x<0.不等式两边同时除以负数y-x,不等号应改变方向才能成立.

已知x-y/xy=3,求分式2x+3xy-2y/x-2xy-y的值.

∵x-y/xy=3∴x-y=3xy2x+3xy-2y/x-2xy-y=[2(x-y)+3xy]/[(x-y)-2xy]=(6xy+3xy)/(3xy-2xy)=9xy/(xy)=9

若y-x/xy=3,求分式2x+3xy-2y/x-2xy-y

(Y-X)÷(XY)=3可变形为Y-X=3XY(2X+3XY-2Y)÷(X-2XY-Y)=(2X-2Y+3XY)÷(X-Y-2XY)={2(x-y)+3xy}÷(X-Y-2XY)={2(3xy)+3x

若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy+y)的值

x+y=5xy(2x-3xy+2y)/(x+2xy+y)=[2(x+y)-3xy]/[(x+y)+2xy]=(2×5xy-3xy)/(5xy+2xy)=7xy/7xy=1再问:若x+1/x=3,求(x

已知:x+y=1,xy=-3,求下列各式的值:(1)x2+y2; (2)x3+y3; (3)x5y+xy5.

再问:能把第三题重新发一遍吗?再答:这三个题本质上式连在一起的再答:这道题应该是希望杯的试题