X [(X+52.8)×5-3.9343]÷0.5-10X
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/21 14:53:17
是这样的:x^5+x^4=x^3(x^2+x)=(x^2+x)[(x^3-1)+1]=(x^2+x)(x^3-1)+x^2+x=[x(x+1)(x-1)](x^2+x+1)+x^2+x=(x^3-x)
展开式的通项为Tr+1=(−12)rCr10x30−5r令30-5r=0得r=6故展开式的常数项为(−12)6C610=10532故答案为10532
1.(x/x-5)=(x-2)/(x-3)x(x-3)=(x-2)(x-5)x^2-3x=x^2-7x+104x=10x=5/22.(6x-1)/(3x+2)=(4x-7)/(2x-5)(6x-1)(
|x-1|+|x-10|表示数轴上x到1的距离+x到10的距离.显然最小值是9,此时x只要在1到10之间就好.类似的,|x-2|+|x-9|的最小值是7,此时x在2到9之间就好.|x-3|+|x-8|
x(1+2+...+9)=x(9-8-7-...-1)x=0记得采纳啊
2x+3x+4x+5x+x+6x+7x=10028x=100x=100/28x=25/7
5x+6.3x=3.39(5+6.3)x=3.3911.3x=3.39x=0.3
|x|
x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)
x
1.2x²-4x-1=0x²-2x-1/2=0x²-2x+1-1-1/2=0(x-1)²-3/2=0x-1=±√(3/2)x1=1+√6/2x2=1-√6/22
证明:x+1=(x+1)(x^2-x+1)=(x+1)(1+1)=2x+2所以x=2x+1x^5+x^2=x^2(x+1)=x^2(2x+2)=2x^3+2x^2=2(2x+1)+2x^2x^5=4x
原式=[x/(x-3)]-[5x/(x²-x-6)]=[x/(x-3)]-(5x)/[(x-3)(x+2)]=[x(x+2)]/[(x-3)(x+2)]-(5x)/[(x-3)(x+2)]=
(3x+2)(4x-7)=(6x-1)(2x-5)12x²-13x-14=12x²-32x+519x=19∴x=1检验:x=1是方程的根两边乘以(x-1)(x+2)得2x(x+2)
#includesintjiesheng(intn)//用于计算阶乘如:3!{if(n=1)rerunn;returnn*hh(n-1)}doubledigui(intn,intx)//用以计算y=x
解题思路:同学你好,本题利用同角三角函数的基本关系求解,具体过程见解析解题过程:
/>(x+2)/(x+1)-(x+3)/(x+2)-(x+4)/(x+3)+(x+5)/(x+4)=1+1/(x+1)-1-1/(x+2)-1-1/(x+3)+1+1/(x+4)=1/(x+1)-1/
(x-2-x+2分之5)÷2x+4分之x-3=(x-2-x+5/2)÷2x+x/4-3=1/2÷2x+x/4-3=1/4x+x/4-3
不太明白你的意思,是二个多项式通分同分母吗?(x+4)/(x^2+4x)=(x+4)/[x(x+4)]=1/x=(x-2)/[x(x-2)(x-5)/[x(x-5)-2(x-5)]=(x-5)/[(x