(1 2y)(1-2y)(12 4y的平方)

(1).（1-y）^2(1+y)(-1-y)=-（1-y）^2(1+y)^2=-[（1-y）(1+y)]^2=-(1-y^2)^2(2).x^2/2+y^2/2=(x^2+y^2)/2=[(x+y)^

∵3y^2-(2y+1)(y-2)=(y-5)(y-1)==>3y^2-2y^2+3y+2=y^2-6y+5==>9y==3==>y=1/3∴原方程的解是y=1/3.

1、4(x-y+1)+y(y-2x)=4x-4y+4+y²-2xy=y²-4y+4-2xy+4x=(y-2)²-2x(y-2)=(y-2x-2)(y-2)2、4x^4-1

原式=(9x^2-3xy+1/4y^2+3xy-1/4y^2)÷(4x^2+4xy+u^2-4xy-y^2)=9x^2÷4x^2=9/4

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1)x(x-y)(x+y)-x(x+y)^2=x((x-y)(x+y)-(x+y)^2)=x(x^2-y^2-x^2-2xy-y^2)=x(-2xy-2y^2)=-2xy(x+y)2)（2a+b)(2

移项：把y移到左边数值移到右边5y+y+5y=2-5/12+1/4-4/311y=1/2y=1/22移项：把y移到右边,数值移到左边-1/4+7/6=5y-3y11/12=2yy=11/24

[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y=[x²-y²-x²-2xy-y²-xy+xy²]/(y/2)=[(x-2)y

.死算呗xy-2x+3y-6=xy+10x-3y-30,2x-y=4xy+3x+y+3=xy+12x-2y-24,3x-y=92式减1式,x=5,y=6

y-[3y-1]=5【y+2]y-3y+1=5y+103y=-9y=-3

4（x-y+1)+y(y-2x)=4x-4y+4+y^2-2xy=(y^2-4y+4)-2x(2-y)=(y-2)^2+2x(y-2)=(y-2)(2x+y-2)

4(x-y+1)+y(y-2x)=4x-4y+4+y^2-2xy=(2-y)^2+2x(2-y)=(2-y)(2-y+2x)4x^4-13x²+9=4x^4-12x^2+9-x^2=(2x^

y^3+5-12y^2+2-3y^2-2分之1y^3-y^2=-1+5-12+2-3+0.5-1=-9.53x-2x^2+5+3x^2-2x-5=3-2+5+3-2-5=2再问：能写的详细一些吗？再答

原式=(9x^2-3xy+1/4y^2+3xy-1/4y^2)÷(4x^2+4xy+u^2-4xy-y^2)=9x^2÷4x^2=9/4

(x-y)^2+12(x-y)+36=(x-y+6)²;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,再问：Guoc过程再答：(x-y)^2+12(x-y

设y'=p,y"=p(dp/dy)y·y''=1+y'^2yp(dp/dy)=1+p^2pdp/(1+p^2)=dy/y(1/2)ln(1+p^2)=ln|y|+c1+p^2=c1y^2p^2=c1y

不显含x型.令y'=p,则y"=pdp/dy,原微分方程可化为yp[dp/dy]+1=p^2即ydp/dy=(p^2-1)/p分离变量p/(p^2-1)dp=dy/y两边积分∫p/(p^2-1)dp=

∵3y^2-(2y+1)(y-2)=(y-5)(y-1)==>3y^2-2y^2+3y+2=y^2-6y+5==>9y==3==>y=1/3∴原方程的解是y=1/3.希望对你有所帮助,

令y'=p,那么y"=dp/dx=dp/dy*dy/dx=p*dp/dy所以原方程可以化为p*dp/dy+p=py即dp=(y-1)*dy等式两边积分得到p=y'=0.5y^2-y+C(C为常数)x=