vb中求两个整数的最大值与最小值编程
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privatesubform_click()n=val(text1)m=val(text2)ifn
#include<stdio.h>int getmax(int a,int b){ re
DimnMaxasInteger,nMinasInteger,nTmpasInteger,nJsqasIntegerDimdSumasDoubleRandomizenTmp=CInt(Rnd*100)
PrivateSubCommand1_Click()RandomizeDima(10)AsInteger,imasasinteger,iminasinteger,Averageasintegerima
帮你写好了,这个是工程文件,下载下来就可以了.以下是源码:PrivateSubCommand1_Click()DimA(10)AsDouble,LAsInteger,BAsDouble,CAsDoub
privatesubcommand1_click()fori=1to15randomizea=int(Rnd*20)+80ifi=1thenmax=a:min=aifmaxathenmin=aprin
PrivateSubCommand1_Click()DimSAsLongS=YueOrBei(24,32)MsgBox"24和32的最大公约数是:"&S,vbInformationS=YueOrBei
LS的回答有可能出来100(三位数)改为a=int(Rnd*100)b=int(Rnd*100)
main(){intm,n,p;inta,b,c,d,e;while(scanf("%d%d%d%d",&a,&b,&c,&d)!=EOF){m=MAX(a&0xF,b&0xF);n=
Dimy%,x%Fori=1To10x=Int(Rnd*100)'[0,99]Printx;Ifi=1Theny=xElseIfy>xTheny=xEndIfNextiPrint"最小值";x如果是N
设a为整数,b为有限小数,按照题意有a+b=ab变形如下:ab-a-b+1=1(a-1)(b-1)=1即整数a-1和小数b-1互为倒数,这样的数有无穷多个.只需整数a使得b=1+1/(a-1)=a/(
inta,b,max;scanf("%d",&a);scanf("%d",&b);max=Max(a,b);intMax(inta,intb){returna>b?a:b;}再问:确定吗这个答案?再答
设这四个数为n,n+1,n+2,n+3n+n+1+n+2+n+3=n(n+3)4n+6=n^2+3nn^2-n-6=0(n-3)(n+2)=0n=3,n=-2这四个数为3,4,5,6或-2,-1,0,
任意6个值,我就以随机产生6个两位正整数为例好了,代码如下:PrivateSubCommand1_Click()Dima(6)AsIntegerFori=1To6Randomizea(i)=Int(R
functionGetData()dimMaxasdouble'最大的数dimminasdouble‘最小的数dimiLasdouble’最大的位置dimalasdouble‘最小的位置dimtota
两数分别是32,48.应该在2的倍数里找,而且接近于一半的数(40附近)
PrivateSubForm_Load()DimXAsLong,YAsLong,KAsLongDimAAsLong,BAsLongA=6B=8X=IIf(A>=B,A,B)'x存入最大值Y=IIf(A
Private Sub Command1_Click() m = Array(2, 7, 9,
PrivateSubCommand1_Click()DimArr(9)AsLong'用于存放产生的10随机数DimiAsLongDimnMaxAsLong'用于存放最大的偶数DimnMinAsLong
二次方程的整数根问题,比起二次方程的实数根,条件更复杂:1、△=b^2-4ac必须为完全平方数;2、-b+√(b^2-4ac)=2ak或-b-√(b^2-4ac)=2ak,其中k为整数两条件必须同时满