tanx/tany等于tan(x/y)吗
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/12 16:24:37
sin(x+y)=sinxcosy+cosxsiny=1/2,sin(x-y)=sinxcosy-cosxsiny=1/3,两式作商得(sinxcosy+cosxsiny)/(sinxcosy-cos
tanX+tanX=2tanXtanX*tanX=tan^2X
tan不像sincos,它是单派循环,7派-x=派-x,tan是奇函数,所以=-x再问:那要是8派减x了再答:。。。高一新生?我刚才已经说清楚了,它是单派。。。再问:第四题怎么做再问:第四题怎么做再问
令a=tanx,a属于Ry=(a^2-a+1)/(a^2+a+1)ya^2+ya+y=a^2-a+1(y-1)a^2+(y+1)a+(y-1)=0判别式大于等于0(y+1)^2-4(y-1)^2>=0
利用tanx=sinx/cosx的定义,左边的一定可以化为sinx和cosx的式子同理右边的可以分解为sinx和cosx的式子二者一定相等
tanx=(2tan二分之x)/(1-tan二分之x的平方),答案是负三分之四.由上面的式子,而且tanx=-4/3,tan(四分之派)=1,所以答案为负七分之一.
tan(x+y)=(tanx+tany)/(1-tanxtany)=6mtanx+tany=5m代入上式tanxtany=1/6tan(x-y)=(tanx-tany)/(1+tanxtany)=1/
根据两角之和的正切角公式tan(π/4)-tan(x)tan(π/4-x)=———————————1+tan(π/4)Xtan(x)因为tan(π/4)=11-tan(x)1-tan(x)所以上式=—
cotx+coty=301/tanx+1/tany=30(tanx+tany)/tanxtany=3025/tanxtany=30tanxtany=25/30=5/6,tan(x+y)=(tanx+t
sin(x+y)=sinxcosy+cosxsiny=1/2sin(x-y)=sinxconsy-cosxsiny=1/3sinxcosy=5/12,cosxsiny=1/12tanx/tany=si
sinx+siny=2sin(x+y)2sin(x/2+y/2)cos(x/2-y/2)=4sin(x/2+y/2)cos(x/2+y/2)cos(x/2-y/2)=2cos(x/2+y/2)cos(
解sinxcosx=(sinxcosx)/(sin²x+cos²x)——分子分母同时除以cos²x=(tanx)/(tan²x+1)
cotx+coty=1/tanx+1/tany=(tanx+tany)/(tnaxtany)即30=25/(tanxtany),所以tanxtnay=5/6tan(x+y)=(tanx+tany)/(
再答:你也可以简单计算!如果是填空或者选择题的话再问:请问填空题怎么简单计算啊
大师教学有过程,先彩后教详解,彩吶我第一时间教谢谢!
tan(x+y)=[tanx+tany]/[1-tanx*tany]=(1/4-3)/(1+3/4)=-11/7
(tanx+tany(/(tanx-tany)分子分母同乘以cosxcosy:=(sinxcosy+cosxsiny)/(sinxcosy-cosxsiny)=sin(x+y)/sin(x-y)
tan(x+y)=(tanx+tany)/(1-tanxtany)0.4=(tany+0.5)/(1-0.5*tany)就可以解出来了.希望对你有所帮助!
可采用凑角变换:这是标准的答题模式,对你今后学习三角函数有很大的帮助.tany=[tan(x+y)-x]tan(x+y)-tanx=-----------------1+tan(x+y)tanx1+3