﹙xy-x的平方﹚÷xy分之x的平方-2xy+y的平方·x的平方分之x-y
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(3x的平方+2xy-2分之1x)-(2x的平方-xy+x)=3x+2xy-x/2-2x+xy-x=x+3xy-3x/2
=x(x-y)/xy²×y/[-(x-y)]=-1/y
=-(x+2y)(x-2y)/(x+y)²×2x(x+y)/(x-2y)=-2x(x+2y)/(x+y)=-(2x²+4xy)/(x+y)
(3x²+2xy-1/2x)-(2x²-xy+x)=3x²+2xy-1/2x-2x²+xy-x=x²+3xy-3/2x
(xy-x的平方)除以xy分之x的平方-2xy+y的平方乘x的平方分之x-y=x(y-x)*xy/(x-y)²*(x-y)/x²=-y再问:不好意思,打错了(xy-y的平方)除以x
=(xy-x的平方)除以(x的平方-2xy+y的平方\xy)乘以(x-y\x的平方)=-x(x-y)×xy/(x-y)2×(x-y)/x2=-y再问:嗯
(xy-x²)÷(x²-2xy+y²)./xy·(x-y)/x²=-x(x-y)·xy/(x-y)²·(x-y)/x²=-x²y(
y的平方-xy分之(x+y)的平方÷{-(x-y)的平方分之y的平方+xy}=(x+y)²/[y(y-x)]÷[-y(y+x)/(x-y)²]=(x+y)²/[y(x-y
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原式=x(x+y)分之x(x-y)=(x+y)分之(x-y)
原式(-xy/3)²*[xy(2x-y)-2x(xy-y²)]=(x²y²/9)(2x²y-xy²-2x²y+2xy²)
原式=xy/(x-y)(x+y)÷(2y)/(x-y)(x+y)=x/2再问:再问:
(x+3y)/(x²+xy)+(y-x)/(xy+y²)=(x+3y)[x(x+y)]-(x-y)/[y(x+y)]=[(x+3y)y-x(x-y)]/[xy(x+y)]=(xy+
3x²y-{2xy-2(xy-3/2x²y)}+xy=3x²y-{2xy-2xy+3/2x²y}+xy=3x²y-2xy+2xy-3/2x²
(x-y)²/(xy)-(x²-y²)/(xy)=(2y²-2xy)/(xy)=(2y-2x)/x
2y-xy分之x的平方-2x=x(x-2)/y(2-x)=-x/y;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,
原式等于:1/[X(X+2Y)].再问:过程再答:原式等于:(x²-4y²)/(x²+4xy+4y²)÷(x²-2xy)=(x²-4y
[(xy+2)(xy-2)-2x的平方y的平方+4]÷(-xy)当x=10,y=25分之1=[x^2y^2-4-2x^2y^2+4]÷(-xy)=[-x^2y^2]÷(-xy)=xy=10*1/25=
(xy-x的平方)÷xy分之x-y=x(y-x)*xy/(x-y)=-x^2y(x的平方+x分之4x的平方-1)乘(1-2x分之x+1)÷x分之1=[x(x+1)分之(2x+1)(2x-1)]乘(1-