sinx cosx怎么化简

3sinxcosx=3/2sin2x,cos平方x化为cos2x形式,再通过公式合并前面两项.

y=1/2cos²x+（根号3）/2sinxcosx+1=(1/2)*(cos2x+1)/2+（根号3）/4*sin2x+1=(1/2)*[cos2x*(1/2)+sin2x*根号3/2]+

(cosX)^2=(1+cos2X)/2sinXcosX=1/2sin2X代入原式中=(1/2)cos2X+(√3/2)sin2X+3/2=sin(∏/6)cos2X+cos(∏/6)sin2X+3/

原式=√3/2*sin2x+(1+cos2x)/2=√3/2*sin2x+1/2*cos2x+1/2=sin2xcosπ/6+cos2xsinπ/6+1/2=sin(2x+π/6)+1/2

f(x)=sinx+(cosx/sinx)cosx;f(x)=sin(x)+(1-sinx*sinx)/sinx;f(x)=sinx+1/sinx-sinx;f(x)=1/sinx;望能看懂!

f(x)=(sin4x+cos4x+sin2xcos2x)/(2-2sinxcosx)=[(sin2x+cos2x)^2-2sin2xcos2x+sin2xcos2x]/(2-2sinxcosx)=(

原式=√3(1+cos2x)/2+1/2*sin2x-√3/2=sin2x*1/2+cos2x*√3/2=sin2xcosπ/3+cos2xsinπ/3=sin(2x+π/3)

主要用了4个公式cos^2x=(1+cos2x)/2sin^2x=(1-cos2x)/2sin2x=2sinxcosxasinx+bsinx=根号(a^2+b^2)sin(x+arctan(b/a))

令sinx+cosx=√2sin(x+a)=t.t∈[-√2,√2]t²=(sinx+cosx)²=1+2sinxcosxsinxcosx=(t²-1)/2y=[(t&#

=(1+cos2x)/2+sin2x/2=根号2/2sin(2x+pi/4)+1/2

原式=1/(sinxcosx)=(sin²x+cos²x)/sinxcosx此时分子分母同除以cos²x原式=(tan²x+1)/tanx是不是哪里有问题?

2cos²x+√3sinxcosx+sin²x=1+cos2x+√3sin2x/2+（1-cos2x）/2=3/2+cos2x/2+√3sin2x/2=3/2+sin（2x+30度

f(x)=2cosx.cos(x-π/6)-√3(sinx)^2+sinxcosx=2cosx*(cosx*cosπ/6+sinx*sinπ/6)-√3(sinx)^2+sinx*cosx=2cosx

f(x)=2(sinx+cosx)+2sinxcosx+1=2(sinx+cosx)+2sinxcosx+(sinx)^2+(cosx)^2=2(sinx+cosx)+(sinx+cosx)^2=(s

f(x)=sin²x+sinxcosx+2cos²x=sin²x+cos²x+sinxcosx+cos²x=1+sinxcosx+cos²x

f(x)=sinxcosx+√3/2cos2x怎么化简=sin2x/2+(√3/2)cos2x=cos60°sin2x+sin60°cos2x=sin(2x+60°)很高兴为您解答,skyhunter

f(x)=cos^2x-2sinxcosx-sin^2x+1=(cos2x+1)/2-sin2x+1/2-sin^2x+1/2=(1/2)*cos2x+1/2-sin2x+(1/2)*cos2x+1/

sin3x+cos3x=sin(x+2x)+cos(x+2x)=sinxcos2x+cosxsin2x+cosxcos2x-sinxsin2x=sinx(2cos²x-1)+2sinxcos

换元设sinx-cosx=tsinx*cosx=(1-t^2)/21-sinx+cosx=1-t接下来化简1/2+(sqrt(2)/2)sin(x-兀/4)