13-X*2=15-X*6

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/26 16:07:11
3x+2(4X+6)=3(6X-15)-13 3X-4(2X+5)=7(x-5)+4(2X+1)

3x+2(4X+6)=3(6X-15)-133x+8x+12=18x-45-1311x+12=18x-587x=70x=103X-4(2X+5)=7(x-5)+4(2X+1)3x-8x-20=7x-3

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550120x=550x=55/12=4.583

x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少?

x(1+2+...+9)=x(9-8-7-...-1)x=0记得采纳啊

2x+3x+4x+5x+x+6x+7x=100

2x+3x+4x+5x+x+6x+7x=10028x=100x=100/28x=25/7

四道方程:2x+6=5x 6x-28=2x 8(x-3.6)=0.8x 15x-110+7x=110

2x+6=5x5x-2x=63x=6x=26x-28=2x6x-2x=284x=28x=78(x-3.6)=0.8x8x-0.8x=28.87.2x=28.8x=415x-110+7x=11015x+

已知2x*x+x-5=0,求代数式6x*x*x+7x*x-13x+11的值

6x^3+7x^2-13x+11=6x^3+3x^2-15x+4x^2+2x-10+21=3x(2x*x+x-5)+2(2x*x+x-5)+21=3x*0+2*0+21=21

(x^2 + x)^2+ (x^2 + x)=6

(x^2+x)^2+(x^2+x)=6(x^2+x)^2+(x^2+x)-6=0(x^2+x+3)(x^2+x-2)=0(x^2+x+3)(x+2)(x-1)=0因为x^2+x+3=x^2+x+1/4

若x^2-8x+13=0求(x^4-6x^3-2x^2+18x+23)

原式=x^4-8x^3+13x^2+10+2x(x^2-8x+13)+(x^2-8x+13)=x^2(x^2-8x+13)+10=10分组代入后得10

因式分解:(1)3x^2+7x+2 (2)5x^2+13x-6=0 (3)6x^2+13x-15=0

(1)3x^2+7x+2=3x^2+6x+x+2=3x(x+2)+(x+2)=(x+2)(3x+1)(2)5x^2+13x-6=05x^2-2x+15x-6=0x(5x-2)+3(5x-2)=0(5x

先化简,再求值:x(x^2-6x-9)-x(x^2-8x-15)+2x(3-x),其中x=3,

x(x^2-6x-9)-x(x^2-8x-15)+2x(3-x)=x^3-6x^2-9x-x^3+8x^2+15x+6x-2x^2=12x=36

X(X的2次方-6X-9)-X(X的2次方-8X-15)+2X(3-X),其中X=1/3. 先化简,再求值

X(X^2-6X-9)-X(X^2-8X-15)+2X(3-X)=X^3-6X^2-9X-X^3+8X^2+15X+6X-2X^2=12x带入X=1/3原式=12*1/3=4

解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)

x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)

(2x^-5x+2/6x^+13x+6)*(6x^-5x-6/6x^-17x+10)*(12x^+8x-15/2x^-x

主要是考察因式分解这方面的技能啊![(2x²-5x+2)/(6x²+13x+6)]*[(6x²-5x-6)/(6x²-17x+10)]*[(12x²+

已知 X=4- 根号3 求 (X*X*X*X-6X*X*X-2X*X+18X+23) / (X*X-8X+15)的值

设x1=4-√3,x2=4+√3,是方程X^2-8X+13=0的两根所以X1^2-8X1+15=2X^4-6X^3-2X^2+18X+23=(X+1)^2*(X^2-8X+13)+10=10所以原式=

15X(3X-8)-4X(2X+3=6X(4X-4)-4谢谢!

45x-120-8x-12=24x-24-445x-8x-24x=120+12-24-413x=104x=104÷13x=8

X^2+X分之6=X^2+X+1

左右都有X^2,故把它们都约去,剩下X分之6=X+1两边都乘以x得6=x平方+x移项x平方+x-6=0因式分解(x-3)(x+2)=0解得x=3或x=-2

方程(x^3-3x^2+x-2)(x^3-x^2-4x+7)+6x^2-15x+18=0的全部相异实根是

x^6+x^5(-1-3)+x^4(-4+3+1)+x^3(7+12-1-2)+x^2(-21-4+2)+x(7+8)-14+6x^2-15x+18=0x^6-4x^5+16x^3-17x^2+4=0