输入一个摄氏温度c ,要求输出华氏温度.公式为f=5 9*c 32,编程流程图

intmain(intargc,char*argv[]){intinput;intret,num;printf("Inputaint:");scanf("%d",&input);for(;;){num

intmain(){floatc,f;printf("pleaseinputthef=");scanf("%f",&f);c=5/9*(f-32);printf("thec=%f",c);}再问：你运

#includevoidmain(){floatc,f;scanf("%f",&f);c=5.0/9*(e-32);printf("%f",c);}

代码#includevoidmain(){doublea,c;scanf("%lf",&a);c=9.0/5*(a-32);printf("%.2lf\n",c);}

我有一本答案是谭浩强的,如果你是用这个的话hi我,这道题目很简单,不看答案都没有问题.我记得里面有这道题目

#includemain(){floattemperature;scanf("%f",&temperature);temperature=5.0/9*temperature+32;printf("%f

#includevoidmain（）{floatc,f；printf（“请输入一个华氏温度：”）scanf（“%f”,&f）；c=（f-32)/9；printf（“摄氏温度为：%5.2f\n”）；}编

你是要求用C语言吗?再问：是再答：这个我可以编，但是你地公式写得不清楚。c代表什么，F代表什么。要是一个代表摄氏，一个代表华氏，那肯定是有等号的。你再好好看看。把公式发过来。再问：C代表摄氏温度，F代

#includemain(){floatc,h;while(1){printf("PleaseinputtheC:");scanf("%f",&c);if(c!=0){printf("TheHis:%

#includevoidmain(){floatF;floatC;scanf("%f",&F);printf("%f",C=5/9*(F-32);}采纳吧少年,这题我们刚做过

5.0不能换成5,否则5/9=0可用float,相应改为floatc;scanf("%f",&c);

华氏转摄氏公式：T℉=1.8t℃+32#includeintmain(){floatf,c;printf("输入华氏温度：\n");scanf("%f",&f);c=(f-32)/1.8;printf

#includemain(){floatf,c;printf("pleaseenterF:");scanf("%f",&f);c=5.0*(f-32.0)/9.0printf("%f",c);}

#includemain(){floatF,C;charflag;loop:printf("Doyouwanttostart(y/n/q)?\n");flag=getch();if(flag=='q'

#include<stdio.h>int main(){    float F,c;   &nbs

#includeintmain(){floatF,c;while(1){printf("请输入华氏温度：");scanf("%f",&F);c=5*(F-32)/9;printf("摄氏温度为：%0.

#includefloatfun(floatC){floatF;F=C*9/5+32;returnF;}voidmain(){floatC,F;printf("输入摄氏温度:");scanf("%f"

用C写吗?#includeintmain(){floatF;printf("请输入华氏温度：");scanf("%f",&F);printf("与华氏%0.3f°相应的摄氏温度为：%0.3f°\n",

#includeintmain(){floatc,f;printf("请输入华氏温度：");scanf(("%f",&f);c=5*(f-32)/9;printf("摄氏温度为：%.2f\n",c);