设xy平方-e的xy方 2=0.求dx分之dy-搜答案-智慧作业帮

原式=4x²y³÷(-1/2xy)²=4x²y³÷[(-1/2)²x²y²]=4x²y³÷[(1/4

[XY(2X-Y)的平方-(-XY的二次方)的二次方]除以8XY=[(2x-y)²-xy³]÷8=[（-2/3-1）²+1/3*1]÷8=（25/9+1/3）÷8=28/

x^3y-2x^2y^2+xy^3=x^3y+2x^2y^2+xy^3-4x^2y^2=xy(x^2+2xy+y^2)-4x^2y^2=xy(x+y)^2-4x^2y^2=12×7×7-4×12×12

由题得x^2y^4=(xy^2)^2=(3/2)^2=9/4

题目应是已知XY的平方=－2,求XY(2X³Y的七次方-5X²Y的五次方-Y)的值已知XY的平方=－2,XY(2X³Y的七次方-5X^2Y的五次方-Y)的值=XY^2(2

对方程取导数y+x(dy/dx)+(dy/dx)=0(dy/dx)(x+1)=-ydy/dx=(-y)/(x+1)

x²+2xy+4y²+x²y²+1=8xy(x²-4xy+4y²)+(x²y²-2xy+1)=0(x-2y)²

x³y-2x²y+xy=xy(x²-2x+1)=xy(x-y)²=1/2×2²=2

xy的平方·(-x的平方y的平方)·(2分之1xy的三次方)的平方=(xy)^2*(-x^2y^2)*(xy)^6/4=-(xy)^10/4=-[(xy)^2]^5/4=-2^5/4=-8

原式=xy(x²-2xy+y²)这一步就很清楚的明白是公式的运用了：a²-2ab+b²=(a-b)²所以=xy(x-y)²将x-y=-1,x

你想说这个问题?z=e^(x^2+2xy)应该是y=e^(x^2+2xy)(2x+2y）i+e^(x^2+2xy)2xj

两边同时求导..得：y-e^xy(yx')=0x'=y/(ye^xy)所以dy/dx=y/(ye^xy)

x²+xy=3xy+y²=-22x²-xy-3y²=2（x²+xy）-3（xy+y²）=6+6=12

原式=-x^3y^6+x^2y^4+xy^2=-(xy^2)^3+(xy^2)^2+xy^2=-(-2)^3+(-2)^2+(-2)=-(-8)+4-2=10

你好!两边对x求导：e^(xy)*(y+xy')-y^2=y'cosy解得y'=(y^2-ye^(xy))/(xe^(xy)-cosy)

2x³-8x²y+8xy²=2x(x²-4xy+4y²)=2x(x-2y)²

∵|x-2a|+(y+3)²=0∴x=2a,y=-3∵A=2x²-3xy+y²-x+2y=8a²+16a+3,B=4x²-6xy+2y²+3

(x的平方-2xy）的平方+2y的平方（x的平方-2xy）+y的4次方=(x^2-2xy+y^2)^2=(x-y)^4

原式=-x³y^6+x²y^4+xy²=-(xy²)³+(xy²)²+(xy²)=-2³+2²+2=

原式=(-4)*(-2)*(x*x²)y³=8x³y³