解方程:3x² 2x-1=0

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/04 06:28:03
解方程(x²-3x)/(x²-1)+(2x-1)/(x-1)=0

两边乘以(x+1)(x-1)得x²-3x+(2x-1)(x+1)=0x²-3x+2x²+x-1=03x²-2x-1=0(3x+1)(x-1)=0∴x=-1/3x

解方程:x+1/x^2-3=1/x

(x+1)/x²-3=1/xx+1-3x²=x3x²=1x²=1/3x=±(√3)/3再问:1/x^2-1+2/x+1=3/x-1再答:������������

(6/x-2)=(x/x+3)-1解方程

两边乘(x+3)(x-2)6x+18=x²-2x-x²-x+66x+18=-3x+69x=-12x=-4/3经检验,x=-4/3是方程的解

解方程:(4/x-2)+(x-1/x-5x+6)+(2/3-x)=0

4/(x-2)+(x-1)/[(x-2)(x-3)]-2/(x-3)=0[4(x-3)+(x-1)-2(x-2)]/[(x-2)(x-3)]=03(x-3)/[(x-2)(x-3)]=0不知道解了~~

解方程 x(2x-4)+3x(x-1)=5x(x-3)+8

x(2x-4)+3x(x-1)=5x(x-3)+82x²-4x+3x²-3x=5x²-15x+88x=8x=1

解方程:2x(x-1)-x(3x+2)=-x(x+2)-12

2x(x-1)-x(3x+2)=-x(x+2)-122x^2-2x-3x^2-2x=-x^2-2x-122x^2-3x^2+x^2-2x-2x+2x=-12-2x+12=0-2(x-6)=0x-6=0

解方程(3x^2+9x+7)/(x+1)-(2x^2+4x-3)/(x-1)-(x^3+x+1)/(x^2-1)=0

方程两边同时乘以x²-1:(3x²+9x+7)(x-1)-(2x²+4x-3)(x+1)-(x³+x+1)=03x^3+9x^2+7x-3x^2-9x-7-(2

解方程(x²+3x+2)(x²-2x-1)(x²-7x+12)+24=0

(x+1)(x+2)(x^2-2x-1)(x-3)(x-4)+24=0(x+1)(x-3)(x+2)(x-4)(x^2-2x-1)+24=0(x^2-2x-3)(x^2-2x-8)(x^2-2x-1)

解方程:2x*x+3x-3=0

2x*x+3x-3=02x*x+3x=3x*x+3x/2=3/2(x+3/4)^2=3/2+9/16(x+3/4)^2=33/16x+3/4=±√33/4x=(-3±√33)/4如还不明白,请继续追问

解方程:2/x^2+x+3/x^2-x-4/x^2-1=0

2/x^2+x+3/x^2-x-4/x^2-1=0(2/x^2+3/x^2-4/x^2)+x-x-1=01/x^2-1=01/x^2=1x^2=1x=1或-1

解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)

x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)

(x^2+x)(x^2+x-3)-3(x^2+x)+8=0解方程

(x^2+x)(x^2+x-3)-3(x^2+x)+8=0(x^2+x)^2-6(x^2+x)+8=0(x^2+x-4)(x^2+x-2)=0x^2+x-4=0x^2+x-2=0(x+1/2)^2=1

解方程1/x=x/(3x-2)

转换一下x^2=3X-2x≠0X≠2/3X^2-3X+2=0(x-2)(X-1)=0x=2X=1

解方程(1-3x)2+(2x-1)(1+2x)-5x=0

(1-3x)2+(2x-1)(1+2x)-5x=01-6x+9x²+4x²-1-5x=013x²-11x=0x(13x-11)=0x=0,x=11/13

(x+1)(x-3)=2x+5解方程

(x+1)(x-3)=2x+5x²-2x-3=2x+5x²-4x=8x²-4x+4=8+4(x-2)²=12x-2=±2√3x=2-2√3,x=2+2√3

解方程:x²+3x-1=x-2

x²+3x-1=x-2x^2+2x+1=0(x+1)^2=0x=-1

x/(x-2)+(x+1)/(x-6)=2x/(x-3) 解分式方程

你好,我认真解答了这道题,看最终没有实数解啊.我希望能帮到你

解方程:|x+2|-|3x+5|=x+1

设X为正数则:(X+2)-(3X+5)=1+X解得X=-4/3设X为负数则:(-X+2)-(-3X+5)=1+(-X)解得X=4/3

几道初一数学题(x^2-1)/(x-3x) +( x-1)/(2x-1)=0 解方程已知方程 x分之3 + x-1分之6

(1)原方程即为:(x2-1)/(-2x)+(x+1)/(2x-1)=0即为:(x2-1)/(2x)=(x+1)/(2x-1)即:(x+1)(x-1)(2x-1)=(2x)(x+1)双方除以(x+1)