解方程:2x^4-7x^3 9x^2-7x 2=0

(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问：第二步那个1是怎么

((X-2)(X-4)-(X-3)^2)/(X-3)(X-4)=((X-5)(X-7)-(X-6)^2)/(X-6)(X-7),-1/(X^2-7X+12)=-1/(X^2-13X+42),6X=30

4x/(x^2+2x+4)-3x/(x^2-3x+4)=-7/3分母不为0,x^2+2x+4和x^2-3x+4均不为0通分x（x^2-18x+4)/(x^2+2x+4)(x^2-3x+4)=-7/3再

x(2x-4)+3x(x-1)=5x(x-3)+82x²-4x+3x²-3x=5x²-15x+88x=8x=1

(x²-x+4)x-(x-1)(x²+2)=x+7x³-x²+4x-x³+x²-2x+2=x+72x+2=x+72x-x=7-2x=5

(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=(x/2)*(2/x(x+2))+(2/(x+2)(x+4))+.+2/(x+8)(x+10)=(x/2)*[1/x

3x(5-3x)-39=2x(7-2x)+5x(8-x)15-9X-39=14-4X+40-5X15-39-14-40=9X-5X-80=4XX=-20如果我没把X和乘号弄混的话,应该是对的再问：15

【解法一】【解法二】5x(x+7)(x+4)=5x(x^2+11X)5x(x²+11x+28)-5x(x²+11x)=05x^3+55x^2+140x=5x^3+55x^25x(x

 再问：2x是怎么得来的

方程两边同时乘以x²-1:(3x²+9x+7)(x-1)-(2x²+4x-3)(x+1)-(x³+x+1)=03x^3+9x^2+7x-3x^2-9x-7-(2

3x【7-2x】+5x【2x-1】=4x【x-3】+5621x-6x^2+10x^2-5x=4x^2-12x+5628x=56x=2x的n次方【x的n次方+9x-12】-3【3x的n+1次方-4x的n

通分得[（x-8）(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(x+8)]/(x+8)(x+3)解得5/(x-3)(x-4)=5/(x+8)(x+3),

(x+8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)[（x-8）(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(

21x-6x^2+10X^2-5x-4x^2+12x-56=028x-56=0x=21/9x^2y^2*(2yx^2-xy^2-2yx^2+2xy^2)=(1/9x^2y^2)*xy^2=1/9x^3

首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(

2x+4x+6x+8x+...+2010x+2012x=1013042x+2x+3x+4x+...+1005x+1006x=5065211006*1007x/2=506521x=1013042/100

(x-3)(x+8)=(x+4)(x-7)+2(x+5)x²+5x-24=x²-3x-28+2x+105x+3x-2x=24-28+106x=6x=1

2(x-3)(x+5)=x^2+(x+2)(x-2)+(x+7)2(x^2+2x-15)=x^2+x^2-4+x+72x^2+4x-30=2x^2+x+33x=33x=11

(1/x-7)+(1/x-1)=(1/x-6)+(1/x-2)1/(X-7)-1/(X-6)=1/(X-2)-1/(X-1)(X-6-X+7)/[(X-7)(X-6)]=(X-1-X+2)/[(X-1

解题思路：高次方程的解法分解因式解题过程：