解方程3(x-7)-2[9-4(2-x)]等于22-搜答案-智慧作业帮

4x^2+2x√(3x^2+x)+x-9=03x^2+x+2x√(3x^2+x)+x^2-9=0[√(3x^2+x)]^2+2x√(3x^2+x)+x^2=9[√(3x^2+x)+x]^2=9√(3x

(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问：第二步那个1是怎么

将x-7/x-9分解成1+2/(x-9)其他分式同理则原方程等价于1/x-9+1/x-5=1/x-6+1/x-81/x-6-1/x-5=1/x-9-1/x-81/(x-5)(x-6)=1/(x-8)(

((X-2)(X-4)-(X-3)^2)/(X-3)(X-4)=((X-5)(X-7)-(X-6)^2)/(X-6)(X-7),-1/(X^2-7X+12)=-1/(X^2-13X+42),6X=30

(9x-7)/(3x-2)-(4x-5)/(2x-3)=1(9x-7)(2x-3)-(4x-5)(3x-2)=(2x-3)(3x-2)18x²-41x+21-12x²+23x-10

当x＞-34时，4x+3=2x+9，2x=6x=3，当x＜-34时，-4x-3=2x+9，6x=-12x=-2．

4x方+x+2x根号下(3x方+x)=[x+根号下(3x方+x)]的平方=9x+根号下(3x方+x)=33x方+x=(3-x)的平方=9-6x+x方2x方+7x=9x=1

再问：2x是怎么得来的

方程两边同时乘以x²-1:(3x²+9x+7)(x-1)-(2x²+4x-3)(x+1)-(x³+x+1)=03x^3+9x^2+7x-3x^2-9x-7-(2

9x+7/3x+2-4x+5/2x+3=154x+14x+12-24x+15x+18=659x=-24x=-24/59

通分得[（x-8）(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(x+8)]/(x+8)(x+3)解得5/(x-3)(x-4)=5/(x+8)(x+3),

4x+7=9x+229x-4x=7-225x=-15x=-32(x-2)-3(4x-1)=9(1-x)2x-4-12x+3=9-9x2x-12x+9x=9+4-3-x=10x=-10

19.3-5x=2x+3-7x=0x=020.7(2x-1)-3(4x-1)=4(3x+2)-114x-7-12x+3=12x+8-12x-4=12x+7-10x=11x=-11/10

(x+8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)[（x-8）(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(

解方程3\4x-7\9=2\5

(3/4)x--7/9=2/5135x--140=72135x=72+140135x=212x=212/135.

首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(

(x-3)(x+8)=(x+4)(x-7)+2(x+5)x²+5x-24=x²-3x-28+2x+105x+3x-2x=24-28+106x=6x=1

（2x-3)(-2x-3)+9x=x（3-4x)－（2x－3）（2x＋3）＋9x＝3x－4x²－（4x²－9）＋9x＝3x－4x²－4x²＋9＋9x＝3x－4x

1、x>=0时,[2x]