若xy≠1,5x2 2011x 9=0,9y2 2011y 5=0,求x y

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/16 13:43:57
xy^5-xy等于多少

原式=xy(y^4-1)=xy(x²+1)(x²-1)=xy(x²+1)(x+1)(x-1)

若x+y=3,xy=1,则(-5x+2)-(3xy+5y)等于多少

-5x+2-3xy-5y因为xy=1所以原式=-5x-5y-1-5(x+y)-1因为x+y=3所以-15-1=-16

5x^2y/-1/2xy*3xy^2

5x^2y/-1/2xy*3xy^2=-7.5x²y²

若1/x-1/y=3,5x+3xy-5y/3x-xy-3y

1/x-1/y=(y-x)/xy=3所以y-x=3xyx-y=-3xy所以原式=[5(x-y)+3xy]/[3(x-y)-xy]=[5(-3xy)+3xy]/[3(-3xy)-xy]=-12xy/(-

已知(x+1)²+|y-1|=0,求2(xy-5xy²)-(3xy²-xy)得值

解(x+1)平方+/y-1/=0∴x+1=0,y-1=0∴x=-1,y=1∴2(xy-5xy平方)-(3xy平方-xy)=(2xy+xy)+(-10xy平方-3xy平方)=3xy-13xy平方=3×(

若1/x+1/y=2,则(2x-xy+2y)÷(3x+5xy+3y)

1/x+1/y=2y+x=2xy(2x-xy+2y)=2(x+y)-xy=3xy(3x+5xy+3y)=3(x+y)+5xy=11xy(2x-xy+2y)÷(3x+5xy+3y)=3xy/11xy=3

(8xy-3x平方)-5xy-2(3xy-2x平方),其中,x=2,y=-1

(8xy-3x平方)-5xy-2(3xy-2x平方)=8xy-3x²-5xy-6xy+4x²=x²-3xy=4+6=10

若x>1,y>0且满足xy=xy,xy=x

由题设可知y=xy-1,∴x=yx3y=x4y-1,∴4y-1=1,故y=12,∴12x=x,解得x=4,于是x+y=4+12=92.故答案为:92.

若x-y=5,xy=6,求x^2-xy^2和x^2y+xy^2

x=-1,y=-6或x=6,y=1代入式子得x^2-xy^2=37或30x^2y+xy^2=-42或42

若1/x+1/y=5,求3x+4xy+3y/x+3xy+y的值

1/x+1/y=5两边乘以xy得y+x=5xy∴x+y=5xy3x+4xy+3y/x+3xy+y=[3(x+y)+4xy]/[(x+y)+3xy]=(15xy+4xy)/(5xy+3xy)=19xy/

若(1)xy>0,(2)xy<0,求|x|/x+|y|+|xy|/xy的值

这个是原题要求的吧|x|/x+|y|/y+|xy|/xy(1)xy>0x,y都大于零或都小于零x,y都大于零时|x|/x+|y|/y+|xy|/xy=|x|/x+|y|/y+|xy|/xy=x/x+y

1若x+2y=0 ,xy不等于0,求分式 x^2+2xy / xy+y^2

因为x+2y=0,所以x=-2y原式=(x^2+2xy)/(xy+y^2)=(4y^2-4Y^2)/(-3y^2+y^2)=0/(-2y^2)又因为xy不等于零,所以x、y君不等于零,所以-2y^2亦

1.先化简再求值(½ x²y+1/5 xy²-¼xy)·(-½xy&#

1.先化简再求值(½x²y+1/5xy²-¼xy)·(-½xy²),其中x=-2y=-½(½x²y+1/5xy

若实数xy满足根号下x+1+(y-5)²则xy的次方值为?

根号下x+1+(y-5)²=0x+1=0,y-5=0x=-1,y=5所以x的y次方=(-1)的5次方=-1

1.若x+y=1,xy=-2,试求代数式(xy+5x-2y)-(-3xy+2x-5y)的值

1.若x+y=1,xy=-2,代数式(xy+5x-2y)-(-3xy+2x-5y)的值=xy+5x-2y+3xy-2x+5y=4xy+3x+3y=4*(-2)+3*1=-8+3=-52.已知一个长方形

若x-y=1,xy=5,则x²y-xy²=?

解x²y-xy²=xy(x-y)=5×1=5a²b+ab²=1∴ab(a+b)=1∵a+b=3∴3ab=1∴ab=1/3再问:a(a-b)-a+b=?再答:=a

若1/x-1/y=3,求5x+2xy-5y/x-4xy-y的值

得y-x=3xyx-y=-3xy原式=-15xy+2xy/-3xy-4xy=-13/-7=13/7

若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy+y)的值

x+y=5xy(2x-3xy+2y)/(x+2xy+y)=[2(x+y)-3xy]/[(x+y)+2xy]=(2×5xy-3xy)/(5xy+2xy)=7xy/7xy=1再问:若x+1/x=3,求(x

若X+Y=3,XY=1,则-5X-5Y+3XY的值是多扫?

-5X-5Y+3XY=-5(x+y)+3xy∵X+Y=3,XY=1∴原式=-15+3=-12

2xy-{5x-3[xy-1/3x(y+1)]-4xy} 去掉括号,并合并.

2xy-{5x-3[xy-1/3x(y+1)]-4xy}=2xy-{5x+x+3xy+xy-4xy}=-6x+3xy-xy