若(x-1)°-2( x-2 )负二次方无意义则x的取值范围-搜答案-智慧作业帮

解析:∵x^(1/2)+x^(-1/2)=3∴x+2+1/x=9,x+1/x=7∴x^2+2+x^(-2)=49∴x^2+x^(-2)=47[x^(3/2)+x^(-3/2)]/[x^2-2+x^(-

x-M≥-1x≥M-1已知解集为x≥2则M-1=2M=33x+M再问：谢谢了

x-m>=-1x>2x>=m-1>2m>33x+m

x+x^-1=3两边平方x^2+2+x^-2=9x^2+x^-2=7两边平方x^4+2+x^-4=49x^4+x^-4=47(x^2-x^-2)^2=x^4-2+x^-4=47-2=45所以x^2-x

x+1/x=a平方,x^2+1/x^2+2=a^2x^2+1/x^2=a^2-2平方,x^4+1/x^4+2=(a^2-2)^2x^4+1/x^4=a^4-4a^2+2x^2+1/x^2+x^4+1/

再答：

x＜2,x＜6,即此题取X＜2,小小取小,大大取大

x²+1=7x两边除xx+1/x=7两边平方x²+2+1/x²=49x²+x^-2=47

limx趋近于负无穷e^(1-x)/(x+x^2)是这个极限吧?洛必达=lim-e^(1-x)/(1+2x)=lime^(1-x)/2=∞也可直接用结论,在趋于无穷中指数函数速度快于幂函数,因此结果为

解由x+x^(-1)=3平方得x^2+x^(-2)+2=9即x^2+x^(-2)=7即[x^2+x^(-2)]^2=7^2即x^4+x^(-4)+2=49即x^4+x^(-4)=47即(x^2-x^(

再答：希望能帮到您！还望采纳谢谢亲

x^3+2x^2+x/x^2+2x-8除以（x/x-2×x+1/x+4)=x(x^2+2x+1)/(x-2)(x+4)/(x(x+1)/(x-2)(x+4))=x(x+1)^2/(x-2)(x+4)*

【x+1】的平方+x【1-x】,=x²+2x+1+x-x²=3x+1当x=-2时原式=-6+1=-5

x=√2-1x+x^1=x+1/x=√2-1+1/(√2-1)=√2-1+(√2+1)/(√2-1)(√2+1)=√2-1+(√2+1)/(2-1)=√2-1+√2+1=2√2

3X^2+4X-2X^2-X+X^2-3X-1=2x^2+3-2x当x=-1/2时,2x^2+3-2x=2*1/4+3-2*1/2=-2又1/2

(5x-4)/(2x-4)-(2x+5)/(3x-6)=负1/2(5x-4)/2-(2x+5)/3=-1/2(x-2)3(5x-4)-2(2x+5)=-3(x-2)15x-12-4x-10=-3x+6

x+y的取值范围是(1,+∞)这是限定规划问题x>=0y>=02x+1<y如图区域蓝色区域设z=x+yy=-x+z显然直线y=-x+z经过A(0,1)时,z有最小值z最小值=0+1=

2^(-x)>x+1当x=0,2^(-0)=1=0+1y=2^(-x)单调递减函数,所以,不等式解集：x