12-2x=10

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x+2x×10=10x+2x+36

x+2x×10=10x+2x+36x+20x=12x+3621x-12x=369x=36x=4

12分之x+10=7X分之x+2

12分之x+10=7X分之x+2解12分之x+10=7分之1X+212分之x=7分之1X+2-1012分之x=7分之1X-8

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550120x=550x=55/12=4.583

解方程(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=1

(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=(x/2)*(2/x(x+2))+(2/(x+2)(x+4))+.+2/(x+8)(x+10)=(x/2)*[1/x

解方程3x=x+4,2.6x-8=2.4x,4x+12=10x+3 ,7x=12-×,2.5x=2x+4,5x+3=6x

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解方程x²+x-6分之5x+x²-x-12分之2x-5=x²-6x+8分之7x-10

5x/(x²+x-6)+(2x-5)/(x²-x-12)=(7x-10)/(x²-6x+8)5x/(x-2)(x+3)+(2x-5)/(x+3)(x-4)=(7x-10)

解分式方程(5-2x)/(x^2-x-12)=5x/(x^2+x-6)+(10-7x)/(x^2-6x+8)得

(5-2x)/(x^2-x-12)=5x/(x^2+x-6)+(10-7x)/(x^2-6x+8)(5-2x)/(x-4)(x+3)=5x/(x+3)(x-2)+(10-7x)/(x-2)(x-4)分

X/15 + X/12 + X/10 = 1365,求X,

同时乘6060×(x/15+x/12+x/10)=1365×604x+5x+6x=8190015x=81900x=81900÷15x=5460很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选

(2x^-5x+2/6x^+13x+6)*(6x^-5x-6/6x^-17x+10)*(12x^+8x-15/2x^-x

主要是考察因式分解这方面的技能啊![(2x²-5x+2)/(6x²+13x+6)]*[(6x²-5x-6)/(6x²-17x+10)]*[(12x²+

x/2+x/8+x/12+x/20=1

60X+15X+10X+6X=12091X=120X=120/91

几道一元二次方程x²+2根号5x+10=0x²+4x+8=2x+113x²-12x=-12

1)2)3)4)x²+2√5x+10=0x²+4x+8=2x+113x²-12x=-122x²+5x-1=0Δ=20-40

解方程.(5x/x²+x-6)+(2x-5/x²-x-12)=7x-10/x²-6x+8

5x/(x²+x-6)+(2x-5)/(x²-x-12)=(7x-10)/(x²-6x+8)5x/[(x+3)(x-2)]+(2x-5)/[(x-4)(x+3)]=(7x

已知f(x)=8x^5-12x 10x^2 求M(x)=f(x)/(-2x^2)

1、M(x)=(8x^5-12x+10x^2)/(-2x^2)=-4x^3+6/x-52、M(-1)=-4*(-1)+6/(-1)-5=4-6-5=-7

(12x-10)/21+(7x-9)/20=(2-x)/15+(8x-9)/12

(12x-10)/21+(7x-9)/20=(2-x)/15+(8x-9)/1220(12x-10)+21(7x-9)=28(2-x)+35(8x-9)240x-200+147x-189=56-28x

(x+12)(x-2)+(x+7)(x+8)-(x+5)(x-10),其中x=2

=x^2+10x-24+x^2+15x+56-x^2+5x+50=x^2+30x+82=4+60+82=146其实,不化简,直接代入=14*0+9*10+7*8=0+90+56=146也很简单

2(0.9-x)+4=4.3.(x+1.8)/8=6.6.12x+12=16x.12x-35=5x.X/0.5-10+2

2(0.9-x)+4=4.31.8-2x+4=4.35.8-2x=4.32x=5.8-4.32x=1.5x=0.75(x+1.8)/8=6.6.x+1.8=52.8x=52.8-1.8x=5112x+

x-1=3x+3 x-3=12-4x 6x-14=5x-10 x+1=2-4x

X-1=3X+32X=-4;X=-2x-3=12-4x5X=15;x=36x-14=5x-10x+1=2-4x5x=1;x=0.2

x*x+2x+x*x+10x+x*x+25+2x+x*x+1+1+16+x*x+4x*x+9-12x+16x*x+4-1

答:结论是无解的设1和4中间的正方形边长为x则左边中间的正方形边长为x+1左下角边长为x+1+x=2x+1所以:右下角正方形边长2x+1+x-4=3x-3所以:最大的正方形底部边长=2x+1+3x-3

解一元二次方程 3x²=10x+83x²-10x+3=0(x+8)(x+1)=-12(x+1)(2x

3x²=10x+83x²-10x-8=0x=(10±√(100+4×3×8)/2*3x=(10±√196)/6x=(10±14)/6∴x1=4x2=-2/33x²-10x