编写一通用的求积函数,从键盘上输入两个数据,输出两数之积,并在主函数中进行调用.

importjava.util.Scanner;publicclassA{//下面的方法是对单个数求阶乘,并返回publicstaticintjieCheng(intn){intsum=1;for(i

#include#definen5intgetmax(inta[]){inti,max;max=a[0];for(i=0.;imax)max=a[i];}returnmax;}intmain(void

#include#include#includevoidmain(){inti,n;charstr[10];charcomp[10][6]={"zero","one","two","three","f

#includeintmain(){inta,b,c;scanf("%d%d",&a,&b);c=a*b;while(a){if(a

#include#includevoidmain(){doublex;doubley;coutx;if(-2

importjava.util.Scanner;publicclassJiecheng{Scannerin=newScanner(System.in);inta=in.nextInt();int

照片啊

#include#defineN10longfun(int(*num)[10],intn){inti,j;longs=1;for(i=0;i再问：能加Q不能另50给你974663046再答：加了，采纳

voidchange(inta,intb){inttemp;temp=b;b=a;a=temp;printf("\n交换后的两个整数为：%d%d\n",a,b);}

PrivateSubCommand1_Click()a=Abs(InputBox("请输入第一个整数","输入数据"))b=Abs(InputBox("请输入第二个整数","输入数据"))c=Abs(

参考：http://hi.baidu.com/%D7%F6%B6%F8%C2%DB%B5%C0/blog/item/a5fcfaf6a09cd93e730eeca8.html;从键盘输入四位16进制数

voidmain{inti=0;//循环用的intscan=0,*s=&scan;charyuefen[][10]={"one","two","忘了3的单词"};//自已把英文写上.chardanci

如果是要求前N个偶数之和：#includeusingnamespacestd;longFunctionadd(intn){longsum=0;for(inti=0;i

importjava.util.Scanner;publicclassOushu{Oushu(){try{System.out.println("请输入n值");Scannerin=newScanne

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PrivateSubCommand1_Click()a=InputBox("请输入数字","提示")b=InputBox("请输入数字","提示")Print"和："&Val(a)+Val(b)Pri

#include#defineN10intgetsum(intn,inta[][N])//要求的通用函数{inti,j,sum=0;for(i=0;i

floatintegral(float(*fun)(float),floata,floatb);其中,a、b表示积分区间,fun是函数指针.floatf1(floatx){floatf;f=1+x*x

//很简单.采纳吧#include#defineN10longfun(int(*num)[10],intn){inti,j;longs=1;for(i=0;i

#include#includedoublef1(floatx){return(1.0*x+x*x);}doublef2(floatx){return(2.0*x*x+3.0*x);}doublef3