编写一个函数f(),实现下列分段函数y=x(x

#include"iostream.h"voidmain(){doubleF,c;coutF;c=(F-32)*5/9;cout

#includedoublefun(doublex,doubley){returnx*x*x+y*y*y;}voidmain(){doublea=fun(3.4,2.8);doubleb=fun(10

#include#includeintmain(){inti=2;intn=0;ints=0;for(;s+i再问：你好。问下system("pause");这句什么意思？再答：暂停控制台。在

#include#include#includeusingnamespacestd;intmain(){floatF,C;coutF;C=5.0/9*(F-32);cout

DATASEGMENTy1DB1y2DB0y3DB-1yDB;(此处存放判定结果)xdb;(此处设定要用的x,代换调“?”即可)DATAENDSCODESEGMENTASSUMECS:CODE,DS:

#!/bin/shfun(){sum=0foriin`seq$1$2`dosum=`expr$i+$sum`doneecho$sum}echo"Pleaseinput2number:"readabex

#include#includevoidmain(){doublex;doubley;coutx;if(-2

intprime(intn){intt;for(t=2;tn/2)return1;elsereturn0;}

f=[1;2];forn=3:10f(n)=f(n-1)+f(n-2);endff=123581321345589

#includeintmain(){inti,j;for(i=5;i>=1;i--){for(j=1;j

/*多项式加法和乘法示例*/#include#include#includeusingnamespacestd;//定义多项式的项类classterm{public:intcoef;//多项式系数in

如果分档少,用if函数分档多,建议做个表格,用vlookup函数你讲的太笼统了.

f(1)=1;f(2)=2;max=20fori=3:maxf(i)=f(i-1)+f(i-2);endf

#include#defineN4#defineM5typedefstruct//定义学生结构体数组{charname[15];floatscore[M];floatave;}ST;STstu[N];

functionyout=myfun1(x,D)%myfun1helph=5%|-h,x>D%y=f(x)=|h/(D.*x),|x|

functiony=f(x)ifx

不是主函数的问题,是fun里的pmax=max;pmin=min;这句错了,这样变成把局部变量max和min的地址赋给pmax和pmin,应该是*pmax=max;*pmin=min;把max和min

1:symsabRspRsdR这一句去掉就可以了.function[Rp,Rd,R]=aa11(a,b)N=[sqrt(51),sqrt(21.8);sqrt(2.3),sqrt(48.5)];N1=

n阶乘的函数factorial(n)再问：要过程，谢谢再答：NN=1whilen>0NN=NN*n;n=n-1;endNN

#includevoidmain(){intx,y;scanf("%f",&x);if(x=10){y=3*x-11;printf("%f",y);}else{y=2*x-1;printf("%f",