编写一个main函数,调用一个函数找出200到300的素数

#includeusingnamespacestd;doublecentigrade(doubleF){doubleC=(F-32)*5.0/9;returnC;}intmain(){doubl

function[X_max,X_min]=yougotit(X)X_max=max(X(:));X_min=min(X(:));end我直接在这里写的.不过估计没错.这个.嗯.有点耍滑.但是就是这样

#includeintsum(intn){ints=0;while(n){s+=n%10;n/=10;}returns;}intmain(void){ints=0;for(int

用递归函数#include#includeintinv(intx);main(){intsum=0,i;for(i=1;i

#includedoublecalRectArea(doubledWidth,doubledHeigh){returndWidth*dHeigh;}voidmain(){doublea,b,mul;s

#includeintfact(intn);usingnamespacestd;intmain(){intn;cin>>n;cout

#includeintfact(intn){if(n==1)return1;elsereturn(n*fact(n-1));}main(){intn;printf("inputanumber:

intjc(intx){returnx==1?1:jc(x-1)*x;}再问：可以编一个完整的么？我直接运行试一下。。。新手，不好意思，，，，谢谢再答：intjc(intx){returnx==1?1

上面是对的,f1是求体积的,f2是求表面积的.

#include <stdio.h>#include <string.h>#include <stdlib.h>void c

#include<stdio.h>#include<stdlib.h>#define Pi 3.14159double square(double

#includevoidshow();voidmain(){show();}voidshow(){printf("Ilovechina!");}

#includemain(){intn;printf("Pleaseenteranumber:");scanf("%d",&n);if(n%2==0)printf("Thenumber%dis偶数\n

sum(n){intsum,i;if(i=1;i

首先你那个a[i]=a[i]*(n-j)/j公式有点问题吧,这样会输出全是1的啊...如果还是按照你这样可以改成如下代码：#include"stdafx.h"#include#include#incl

#includemain(){longintn,i,j,k;doublem;printf("请输入数字'n':");scanf("%d",&n);if(n%2==1){for（i=0;i0){for（

#include#includevoidb1(){floatl,s,k;inta,b,c,h;printf("\n");printf("\n");printf("输入a,b,c的值\n");print

什么事指针函数?不知道这个但是完成上面的题貌似很简单

#includeintfun(char*pszText,intnLen){intnCount=0;charchTemp=0;for(inti=0;i='a'&&chTemp='A'&&chTemp

//今天被百度吞了4份代码,上帝保佑这个别被吞了,哥的分数啊.#includeintmain(){intn,i,j;scanf("%d",&n);for(i=1;i