java编程,输入一个数,判断奇偶性

packagetest1;importjava.util.Scanner;publicclassTest6{publicstaticvoidmain(String[]args){Scannerinpu

#include"stdio.h"#include"math.h"main(){inti,n,flag=1;printf("PleaseInputanumber:");scanf("%d",&n);f

DimXAsInteger这句出的毛病.你直接把它定义成整数型变量,输入3.5直接四舍五入转换为4.把它换成DimXAsSingle

#includeintmain(){intm[10],i,j=0,k;longn;scanf("%ld",&n);k=n;while(k>0){k/=10;j++;}i=j;while(i--){m[

#includeintmain(){inti;voidfun(inta);printf("输入数字：");scanf("%d",&i);fun(i);return0;}voidfun(inta){if

#include "stdio.h"main(){ char s[81],c; int i,j=0,num=0,word=0;&n

importjava.util.Scanner;publicclassHuiwen{publicstaticvoidmain(String[]args){Scannerin=newScanner(Sy

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){Scannerinput=newScanner(S

importjava.awt.*;importjava.awt.event.*;classTestimplementsActionListener{TextFieldintext,outtext;Bu

publicstaticvoidmain(String[]arg){intk=0;intm=0;System.out.println("输入一个四位数");Scannerinput=newScanne

#includevoidmain(){inti,j,k,m;printf("inputdata:");scanf("%d",&m);/*输入一个3位数*/i=m/100;j=(m-100*i)/10;

PrivateSubCommand1_Click()DimaAsLongDimiAsLongDimsAsBooleans=Truea=InputBox("请输入一个自然数","输入")'-------

//提示：153370371407是水仙花数#includevoidmain(){inti,j,k,n;printf("请输入一个三位整数\n");scanf("%d",&n);i=n/100;/*分

//看好记事本写的Judge.javapublicclassJudge{publicstaticvoidmain(String[]args){try{if(args.length!=3){Sy

package zhidao;import java.util.InputMismatchException;import java.util.Scanner;publi

#include"stdio.h"main(){intx;printf("请输入一个整数");scanf("%d",&x);if(x%2==0)printf("%d是偶数\n",x);elseprin

publicclassTest{publicstaticvoidmain(String[]arsg){inttemp=1000009;StringtempStr=1000009+"";//转换成字符串

给你提供一个思路,定义1,2,3,4,5,6,7,8,9,0,十,百,千,万的拼音,然后按照你的读法把输入的数字先判断是几位数,然后按照规则输出就可以了

importjava.util.Scanner;classtest7{publicstaticvoidmain(Stringargs[]){Scannerscan=newScanner(System.

importjava.util.*;publicclassMath{publicstaticvoidmain(Stringargs[]){inta,b;Scannersc=newScanner(Sys