java编程,从键盘输入一个正整数n,计算n!

importjava.util.Scanner;publicclassDemo{publicstaticvoidmain(String[]args){Scannersc=newScanner(Syst

importjava.io.*;importjava.util.*;classMain{publicstaticintgcd(intm,intn){while(true){if((m=m%n)==0)

packagetest1;importjava.util.Scanner;publicclassTest6{publicstaticvoidmain(String[]args){Scannerinpu

importjava.util.Scanner;publicclassSum{publicstaticvoidmain(String[]args){Scanners=newScanner(System

importjava.util.Arrays;importjava.util.Scanner;publicclassDataCompare{\x09publicstaticvoidmain(Strin

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){Scannerin=newScanner(Syst

如图：

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){System.out.print("请输入第一个整

#includevoidmain(){\x09inta;\x09scanf("%d",&a);\x09printf("%d*%d=%d\n",a,a,a*a);}//运行情况：33*3=9请按任意键继

packageABC;importjava.io.*;publicclassdistantmoon{publicstaticvoidmain(String[]s)throwsException{

看看谁的效率高过我importjava.util.Arrays;importjava.util.InputMismatchException;importjava.util.Scanner;publi

#includevoidmain(){inti,j,n;printf("请输入n的值：\n");scanf_s("%d",&n);for(i=1;i

#includevoidprint(intspace,intnum,inttype){while(space--)putchar('');if(type){while(num--)putch

#includeintk;voidshow(){chara;printf("Pleaseinputtheletter.\n");scanf("\n%c",&a);printf("Theletter's

publicclassJs{privatedoublea;privatedoubleb;privatedoublec;Js(doublea,doubleb,doublec){this.a=a;this

我觉得这才是楼主的意思吧,首先判断能否同时被5和6整除,如果不能再单独判断是否能被5或者6整除.importjava.util.Scanner;publicclassTest{publicstatic

其实这种逻辑运算的,提现不错Java的面向对象的概念的,你直接写逻辑语句就好,首先判断等边,即if(a==b==c)System.out.print("该三角形是等边三角形");这样写下去就好了.希望

#includevoidmain(){intn;sacnf("%d",&n);if(n%27==0)printf("Yes\n");elseprintf("No\n");}

classOddSum//定义类{publicstaticvoidmain(Stringargs[])//main方法{intsum=0;//定义一个整形变量for(inti=1;i

哥们怎么又是你来?再问：您会不会的啊再答：packagetestt;importjava.util.Scanner;publicclassTest{\x09publicstaticvoidmain(S