用c语言判断输入一个整数n能否被5和7同时整除

#includevoidmain(){intN,status=0;printf("输入这个数:");scanf("%d",&N);if(N%3==0)status++;if(N%5==0)status

代码如下#includeintasd(inta){inti,t=0;for(i=2;i

#includeintmain(){intn;scanf("%d",&n);if(n>0){if(n%2)printf("此数为正数且为奇数.");elseprintf("此数为正数且为偶数");}e

只学循环完全可以办到,关键是要动脑啊#includevoidmain(){\x09intn,m,max,i;\x09max=0;\x09printf("PleaseInputANumber:\n");

我把SCANF里的中文去掉就正常了.

第一个问题:#include#includevoidQuickSort(int*pData,intleft,intright);voidmain(){inta[]={20,11,0,5,8,9,5,3

#include"stdio.h"#include"stdlib.h"intf(intn){while(n>=9){if(n%10==9){return0;}else{n=n/10;}}return1

a+b>cabs(a-b)再问：能编个完整的给我吗？谢谢。新手，看不懂啊……不胜感激再答：#includeinta,b,c;scanf("%d,%d,%d",&a,&b,&c);if(a>0&&b>0

#includeintmain(){inta;intb=0,c=0,d=0;scanf("%d",&a);if(a%5==0)c=1;if(a%7==0)d=1;elseif(c==1&&d==1)p

intiIsRunAround(intnNum){intnCount=0;//位数intnStep=0;intnCur=nNum;intarrNumber[10];//各位数,个位到最高位intarr

感觉像是ACM的题.N

使用了数组的动态分配,看不懂的话我还有其他方案#include#includeboolprime(intnum){boolflag=true;if(num

以下是关键代码intnum;//这个是要你判断的数if(num%3==0&&num%5==0)//判断能否被整除printf("能被3和5整除");

#includevoidmain(){\x09longa;\x09printf("inputanumber:\n");\x09scanf("%d",&a);\x09if(a%3==0&&a%5==0&

inta,b;scanf("%d%d",&a,&b);while(a{intt=a;a=b;b=t;}if(a%b==0)printf("a能被b整除");elsepr

#include"stdio.h"main(){intx;printf("请输入一个整数");scanf("%d",&x);if(x%2==0)printf("%d是偶数\n",x);elseprin

#includemain(){inti,j,N,t,k=0;intscore[100];printf("请输入整数的个数N：\n");scanf("%d",&N);printf("请输入N个整数：\n

#includeintmain(){inta;intb=0,c=0,d=0;scanf("%d",&a);if(a%3==0)b=1;if(a%5==0)c=1;if(a%7==0)d=1;if(b*

inti,a,n;int*pl=NULL;printf("inputn:");scanf("%d",&n);if(n>0){pl=(int*)malloc(n*sizeof(int));}for(i=

#include#includevoidmain(){\x09intn,i;\x09scanf("%d",&n);\x09if(n==1)\x09{\x09\x09printf("1isnothing