fx等于4x方加2分之4x方,求faf1-a
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x²-x-1=0,所以x²=x+1,x^4=(x+1)²=x²+2x+1=x+1+2x+1=3x+2,x^5=(3x+2)x=3x²+2x=3(x+1
已知x方加y方减2x加4y等于-5x方+y方-2x+4y+5=0x方-2x+1+y方+4y+4=0(x-1)方+(y+2)方=0所以x-1=0,y+2=0所以x=1,y=-2如果不懂,请追问,祝学习愉
A/(X+2)-B/(A-2)=4X/(X²-4)[A(X-2)]/[(X+2)(X-2)]-[B(X+2)]/[(X+2)(X-2)]=4X/(X²-4)(AX-2A)/(X
看你的题目都看了很少时间(x-4)/(x^2-1)÷(x^2-3x-4)/(x^2+2x+1)+1/(x-1)=(x-4)/(x^2-1)[(x^2+2x+1)/(x^2-3x-4)]+1/(x-1)
等于多少啊,是2+11还是2x+11在我回答的右上角点击【采纳答案】再问:2x再答:我就说嘛过程如下:x^2+4x+8=2x+11x^2+2x-3=0(x+3)(x-1)=0x+3=0或x-1=0x=
(x^2+5)/√(x^2+4)=√(x^2+4)+1/√(x^2+4)令t=√(x^2+4),则t≥2y=t+1/t单调递增,t=2时,ymin=5/2再问:那个x方加5怎么就等于根号x方加4加1再
再答:记得采纳哦
x²+2xy+4y²+x²y²+1=8xy(x²-4xy+4y²)+(x²y²-2xy+1)=0(x-2y)²
2-x分之x-x方+4x+4分之4-x方=2-x/x-x²+4x+4/4-x²=2-1-x²+4x+1-x²=2+4x-2x²
定义域:x属于R.值域:[-1,1]
X^2+y^2=4求式=x^2-2√3-y^2=x^2-2√3-4+x^2=2x^2-2√3-4而x^2≤4则X^2=4时,原式最大为-2√3
x^2+y^2=4,设x=2cosa,y=2sina,则x^2-2√3xy-y^2=4(cosa)^2-8√3cosasina-4(sina)^2=4cos2a-4√3sin2a=8cos(2a+60
(x+y)/(x)=31+(y/x)=3得:y/x=2则:(x²+y²)/(x²-xy+y²)【分子分母同除以x²】=[1+(y/x)²]/
2x³+3x³-4x³=(2+3-4)x³=x³
x+1/x=4得x^2+2+1/x^2=16x^2+1/x^2=14x四次方加x平方加1分之x平方=x^2/(x^4+x^2+1)=1/(x^2+1+1/x^2)=1/15
x方减2x减3分之3等于2x方加4x减1将等号左边项移到右边,整理得:x平方+6x=0x(x+6)=0x=0或x+6=0x=-6再问:抱歉是我水平不够没表达完整意思是3/(x平方-2x-3)=2x平方
就比喻a+b=5两边平分得a+b+2ab=25那个2就是2ab=2
这个用换元法令a=x/(x²+2)则(x²+2)/x=1/aa+1/a=-10/33a²+10a+3=0(3a+1)(a+3)=0a=-1/3,a=-3x/(x²