求方程x^3 x^2-3x-3=0在1.5附近的根-搜答案-智慧作业帮

[x(x+3)][(x+1)(x+2)]=24(x²+3x)[(x²+3x)+2]-24=0(x²+3x)²+2(x²+3x)-24=0(x²

x(2x-4)+3x(x-1)=5x(x-3)+82x²-4x+3x²-3x=5x²-15x+88x=8x=1

2x(x-1)-x(3x+2)=-x(x+2)-122x^2-2x-3x^2-2x=-x^2-2x-122x^2-3x^2+x^2-2x-2x+2x=-12-2x+12=0-2(x-6)=0x-6=0

是方程叫恒等式方程X的解是所有实数

#include#includeintmain(){doublex=1,x2;do{x2=x;x-=(2*x*x*x-4*x*x+3*x-6)/(6*x*x-8*x+3);}while(fabs(x-

intf(floatx)返回值,错了.

3(X+1)-(X-1)=KX,令X=0,得：3+1=0,舍去,令X=1,得6=K,∴K=6.3X+3-X+1=KX(2-K)X=-4,当K-2=0,即K=2时,原方程无解,当2-K≠0,X=-4/(

x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)

(x^2+x)(x^2+x-3)-3(x^2+x)+8=0（x^2+x)^2-6(x^2+x)+8=0(x^2+x-4)(x^2+x-2)=0x^2+x-4=0x^2+x-2=0(x+1/2)^2=1

设x1=4-√3,x2=4+√3,是方程X^2-8X+13=0的两根所以X1^2-8X1+15=2X^4-6X^3-2X^2+18X+23=(X+1)^2*(X^2-8X+13)+10=10所以原式=

方程3+2x=5x

3+2x=5x5x-2x=33x=3x=1

（x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6)(x+2-1)/(x+2)+(x+7-1)/(x+7)=(x+3-1)/(x+3)+(x+6-1)/(x+

x/1*2+x/2*3+...+x/2007*2008=2007x(1-1/2+1/2-1/3+...+1/2007-1/2008)=2007x(1-1/2008)=2007(2007/2008)x=

2(x-3)(x+5)=x^2+(x+2)(x-2)+(x+7)2(x^2+2x-15)=x^2+x^2-4+x+72x^2+4x-30=2x^2+x+33x=33x=11

|x-3|+|x+2|=4分3个区间讨论x>=3x-3+x+2=4x=5/2(不合要求)-2<=x<33-x+x+2=4(不是方程,等式也不成立)x<-23-x-(x+2)=4

由题意知：X不等于0方程可化为4/(X^2+2X+1)+5/(X^2+2X-5)+3/2=0设X^2+2X=Y则:4/(Y+1)+5/(Y-5)+3/2=0然后通分:Y^2-2Y-15=0所以Y=5O

你好,我认真解答了这道题,看最终没有实数解啊.我希望能帮到你

2x-3=4x-9求方程解!

2x-4x=-9+3-2x=-6x=3

解方程：(x-2)(x^2-6x-9)=x(x-5)(x-3)将方程展开：X^3-6x^2-9x-2x^2+12x+18=x^3-8x^2+15x合并同类项得：12x=18则x=18/12=3/2