e∧x-e∧y=sin(xy)y

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e^x+e^y=sin(xy),求dy/dx.怎么求

将y看成是关于x的函数即y=f(x)我们在求导的同时要记得y也要对x求导即dy/dx我们两边分别对x求导得e^x+e^y*dy/dx=cos(xy)*(y+x*dy/dx)移项e^x-y*cos(xy

协方差公式Cov(X,Y)=E(((X-E(X))(Y-E(Y)))即Cov(X,Y)=E(XY)-E(X)E(Y)中

.你要知道随机变量{X,Y}的联合分布的啊,比如是某个概率测度\mu(x,y)那么E(XY)=\intxyd\mu(x,y)

求下列导数:sin(x+y)=sinx+siny e^x+x=e^y+y

再问:大哥,你题目看错了。。。再答:哪里有错?再问:第一条等式就错了。。是sin(x+y)=sinx+siny。后面是cos(x+y)·(1+y')=cosx+cosy·y'?再答:OK,那我改下

设y=y(x)由方程e^xy+sin(xy)=y确定,求dy/dx.

e^(xy)+sin(xy)=y(y+xy')e^(xy)+(y+xy')cos(xy)=y'y'=(ye^(xy)+ycos(xy))/(1-xe^(xy)-xcos(xy))

e^(2x-y)—sin(xy)=e-1,确定隐函数y=f(x)在点(0,1)处的法线方程为

两边对x求导:[e^(2x - y)](2 - y') - [cos(xy)]*(y + xy')&nb

sin (x^2+y^2)+e^x-xy^2=0求dy

sin(x^2+y^2)+e^x-xy^2=0左右微分得到cos(x^2+y^2)*(2xdx+2ydy)+(e^x)dx-(y^2)dx-2xydy=0余下的求出dy就可以了

y=sin(e∧x+1),求dy

y=sin(e∧x+1)dy=cos(e^x+1)d(e^x+1)=e^xcos(e^x+1)dx

COV(X,Y)=E(XY)-E(X)E(Y)怎么出来的

Cov(X,Y)=E(((X-E(X))(Y-E(Y)))根据协方差定义=E(xy-xE(y)-yE(x)+E(x)E(y))=E(xy)-E(x)E(y)-E(x)E(y)+E(x)E(y)=E(x

e^y+ln(xy)-e^(-x)=0,求y'

两边求导得y'·e^y+(y+xy')/(xy)+e^(-x)=0

E[(X-E(X))*(Y-E(Y))]=E(XY)-E(X)*E(Y)这个公式怎么证明?

要注意E(kX)=kE(X),k是常数E[(X-E(X))*(Y-E(Y))]=E[XY-XE(Y)-YE(X)+E(X)E(Y)]=E(XY)-E(X)E(Y)-E(Y)E(X)+E(X)E(Y)=

设随机变量X,Y满足E(XY)=E(X)E(Y),则

若独立则不相关,不相关不一定独立.设A,B独立P(A)P(B)=P(AB)cov(x,y)=E(XY)-E(X)E(Y)=E(X)E(Y)-E(X)E(Y)=0,因此A,B不相关.反之,A,B不相关c

(1)y-sin(Inx)求y (2)(e^x+y)-xy=0求dy

第一题问得不清楚,看不懂.第二题,两边求导,得e^x+y'-(x'y+xy')=0整理得,dy=(e^x-y)*dx/(x-1)

设方程e^(x+y) + sin(xy) = 1 确定的隐函数为y=y(x),求y'和y'|x=0

e^(x+y)+sin(xy)=1e^(x+y)*(1+y')+cos(xy)(y+xy')=0y'*[e*(x+y)+xcos(xy)]=-[ycos(xy)+e^(x+y)]y'=-[ycos(x

设隐函数y=y(x)由方程x^y-e^y=sin(xy)所确定,求dy

化为:e^(ylnx)-e^y=sin(xy)两边对x求导:e^(ylnx)(y'lnx+y/x)-y'e^y=cos(xy)(y+xy')y'[lnxe^(ylnx)-e^y-xcos(xy)]=[