dy dx-y (x-2)=2

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求由方程xy=ex+y所确定的隐函数的导数dydx

方程两边求关x的导数ddx(xy)=(y+xdydx);     ddxex+y=ex+y(1+dydx);所以有  (y+xdy

求解微分方程dydx

由微分方程dydx=2xy,得dyy=2xdx(y≠0)两边积分得:ln|y|=x2+C1即y=Cex2(C为任意常数)

6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5

设x-y=mx+y=n则6m-2n=143m+n=5解得m=2n=-1即x-y=2x+y=-1解得x=1/2y=-3/2

x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20

由(1)得3x+3y+2x-2y=365x+y=36(3)由(2)得4x+4y-3x+3y=-20x+7y=-20(4)(3)×7-(4)得34x=272∴x=8把x=8代入(3)得y=-4∴x=8y

y'-2y=(e^x)-x

首先求齐次方程通y'-2y=0特征方程:x-2=0x=2为特征根∴y=Ce^(2x)设方程的一个特解为y=Ae^x+ax+b代入方程:Ae^x+a-2Ae^x-2ax-2b=-Ae^x-2ax+a-2

设函数y=y(x)由方程ln(x2+y)=x3y+sinx确定,则dydx|

方程两边对x求导得2x+y′x2+y=3x2y+x3y′+cosxy′=2x−(x2+y)(3x2y+cosx)x5+x3y−1由原方程知,x=0时y=1,代入上式得y′|x=0=dydx|x=0=1

数学题已知p=x^/x-y-y^/x-y,q=(x+y)^-2Y(X+Y),

你的题是什么意思?“^/”是什么意思?

已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y

X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)

因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6

[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013

先一个一个的展开括号项,再同项合并就行了啊[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x=[xx-xy-(xy-yy)+x(x-y)+y(x-y)]÷2x=[xx-xy-xy+yy+xx-

求微分方程dydx+y=e

这是一阶线性微分方程,其中P(x)=1,Q(x)=e-x∴通解y=e−∫dx(∫e−x•e∫dxdx+C)=e−x(∫e−x•exdx+C)=e−x(x+C).

先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y

解(x-y)(x+y)-(x-2y)²+x(3x-5y)-(x-y)(x-2y)=(x²-y²)-(x²-4xy+4y²)+(3x²-5xy

已知4x=9y求(1)x+y/y (2)y-x/2x

4x=9yx=9/4*y(1)(x+y)/y=[(9/4)y+y]/y=(9/4+1)y/y=9/4+1=13/4(2)(y-x)/2x=[y-(9/4)y]/[2*(9/4)y]=(1-9/4)y/

matlab solve函数 xmaxr=solve(dydx,x)

dydx要是等式才行吧.如果是的话,这句话就是求这个等式的根,用r表示x.

解方程组(x+y)(x-2y)=-5 (x-y)(x+2y)=7

展开x^2-2y^2-xy=-5x^2-2y^2+xy=7所以x^2-2y^2=1xy=6上式除以下式,解分式方程x/y=3/2或-4/3(舍去)所以x^2=9y^2=4x=3y=2或x=-3y=-2

y"-2y'+2y=x*(e^x)*cosx

算起来好像很复杂,我算出的是:(x/4)(xsinx+cosx)e^x-(e^x*sinx)/8不知道对不对.

设函数y=y(x)由方程ex+y+cos(xy)=0确定,则dydx

在方程ex+y+cos(xy)=0左右两边同时对x求导,得:ex+y(1+y′)-sin(xy)•(y+xy′)=0,化简求得:y′=dydx=ysin(xy)−ex+yex+y−xsin(xy).