dx y dy x=0,yx=3=4

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已知x2+y2-2x-4y+5=0,分式yx−xy

∵x2+y2-2x-4y+5=0,∴x2-2x+1+y2-4y+4=0,(x-1)2+(y-2)2=0,∴x=1,y=2,∴yx−xy=2-12=1.5;故答案为:1.5.

已知实数x,y满足方程x2+y2-4x+1=0,求yx

方程x2+y2-4x+1=0表示以点(2,0)为圆心,以3为半径的圆.设yx=k,即y=kx,由圆心(2,0)到y=kx的距离为半径时直线与圆相切,斜率取得最大、最小值,由|2k−0|k2+1=3,解

若x+y=4,xy=3,求yx

∵x+y=4,xy=3,∴原式=x2+y2xy=(x+y)2−2xyxy=16−63=103.

已知3x-5y=0,则分式x−2yx+3y

∵3x-5y=0,∴x=5y3,∴原式=5y3−2y5y3+3y=-111.

未知数的数学题x^2+3x+4=yx=?

此方程有无数解这里要把x^2+3x看做一个整体

已知x-3y=0,求2x+yx

2x+yx2-2xy+y2•(x-y)=2x+y(x-y)2•(x-y)(2分)=2x+yx-y;(4分)当x-3y=0时,x=3y;(6分)原式=6y+y3y-y=7y2y=72.(8分)

(x-3)的平方+y=2的绝对值=0则yx的值为多少?

(x-3)²+|y+2|=0∵(x-3)²≥0|y+2|≥0∴当且仅当他们都为0时他们的和为0∴x-3=0y+2=0x=3y=-2

已知3x2+xy-2y2=0,求(x+yx-y+4xyy

原式=[(x+y)2(x-y)(x+y)+-4xy(x-y)(x+y)]×(x+3y)(x-3y)(x+3y)(x-y)=x-3yx+y,由已知得(3x-2y)(x+y)=0,因为x+y≠0,所以3x

已知x2-4xy+4y2=0,那么分式x-yx+y

∵x2-4xy+4y2=0,∴(x-2y)2=0,∴x=2y,∴x-yx+y=2y-y2y+y=13.故分式x-yx+y的值等于13.

xy+yx=10x,y是多少

xy+yx=10x+y+10y+x=11x+11y=100+x10x=100-11yx=10-1.1y所以y只能是0

已知x-y=4xy,则2x+3xy-2yx-2xy-y

∵x-y=4xy,∴2x+3xy-2yx-2xy-y=2(x-y)+3xyx-y-2xy=8xy+3xy4xy-2xy=112.故答案为:112.

xy=yx 有什么关系?

乘法交换律,所以相等

已知2x2-3xy+y2=0(xy≠0),则xy+yx的值是(  )

根据题意,2x2-3xy+y2=0,且xy≠0,故有(yx)2−3yx+2=0,即(yx−1)(yx−2)=0,即得yx=1或2,故xy=1或12,所以xy+yx=2或212.故选A.

已知:a=x−yx+y+3

由题意得,x−y=2x−2y+3=3,解得:x=4y=2,则可得a=3,b=2,b-a=-1,-1的立方根为:-1.

已知2x2-xy-3y2=0,求x−yx+y

2x2-xy-3y2=0,(2x-3y)(x+y)=0,解得:2x-3y=0或x+y=0(分母为0,舍去),解得:x=3y2,则x−yx+y=3y2−y3y2+y=y5y=15.

已知x2+3xy-4y2=0(y≠0),则x−yx+y

∵x2+3xy-4y2=0(y≠0),∴(x+4y)(x-y)=0,∴x+4y=0或x-y=0,∴x1=-4y,x2=y,∴x−yx+y=−5y−3y=53或x−yx+y=0,故答案为:53或0.

x+2y=(yx)/4=(2x+1)/3 二元一次方程解

解答如下:x+2y=(yx)/44x+8y=xyxy-8y=4x(x-8)y=4x当x≠8时(x=8不成立)y=4x/(x-8)x+2y=(2x+1)/32y=(2x+1)/3-x2y=(1-x)/3

已知5x2-xy-6y2=0,则yx

∵5x2-xy-6y2=0,∴(5x-6y)(x+y)=0,∴5x-6y=0,x+y=0,∴5x=6y,x=-y,∴yx=56或-1.故答案为:56或-1.

xy*yx=2268

即(10x+y)*(10y+x)=2268101xy+10x²+10y²=2268因为后面的10x²+10y²只可能是整十的数,所以2268中的个位8要靠101