c语言输入20个数求出比平均值小的数

#includevoidmain(){inta[10],i,count1=0,count2=0,sum1=0,sum2=0;floataverage1,average2;for(i=0;i

mian(){floats1=0,s2=0,x;intn1=0,n2=0,i;for(i=0;i0){s1+=x;n1++;}if(x

#includeintmain(void){intx[10];intsum=0;inti=0;intavg=0;for(i=0;i

#include/*含有scanf和printf必需的头文件*/voidmain(){inta[20],i,max;/*定义变量*/for(i=0;i

假设是用a数组存放的数据intsum=0,i,num=0,average;for(i=0;i

#includeintmain(){inti;doublen[20];doublesum=0.0,average;for(i=0;i

#includevoidmain(){inti,k,n=0,m=0;floatfu,zhen;inta[10000];k=0;while(scanf("%d",&a[k])!=EOF)k++;fu=0

#include"stdio.h"main(){floata[20],avg=0.00;inti;printf("Pleaseinputdatas!\n");for(i=0;i

main(){intmax,min,i,x;floatave;scanf("%d",&x);max=min=ave=x;for(i=0;imax)max=x;if(x

给你写了,你看看吧#includeintmain(void){inta[20],i,j,sum=0,temp;for(i=0;i

#include“stdio.h”main(){floata[20];//这里给20个数开辟存储空间,这里定的是浮点型,//你可以根据自己的需要指定数据类型floatsum=0,avrage;inti

#include#includeintmain(){intnumber[10];//存输入的十个数floatodd=0.0;//奇数平均值floateven=0.0;//偶数平均值intji=0;//

/*C语言输入十个数,判断正数的个数以及它们的平均值*/#include"stdio.h"voidmain(){floatave=0;intval;inti;intn=0;floatsum=0;pri

#include<stdio.h>int main(){  int a[10],i,num=0;  float ave

#include<stdio.h>intmain(void){intx[10];intsum=0;inti=0;intavg=0;for(i=0;i<10;i++)scanf("%d

#includevoidmain(){inti;intnum[10];intsum=0;for(i=0;i{scanf("%d",&num[i]);sum+=num[i];}floatavg=(flo

#includevoidmain(){\x09\x09inti,a,n,j=0;\x09floats=0;\x09\x09\x09printf("请输入整数的个数:");\x09scanf("%d",

是要输入20个数到数组啊?这样：#includevoidmain(){inta[20],i,s1=0,s2=0,sum1=0,sum2=0;printf("请输入20个数：");for(i=0;i

#includevoidmain(){inti,b=0;floatp,a[5],sum;for(i=0;i

#include"stdio.h"main(){intm,i,a[10000];floatave;printf("inputnumber");scanf("%d",&m);for(i=0;i