C语言,输入三个字符,并使其从小到大输出,用函数实现数据的交换

#include#includevoidmain(){printf("请数输入一个字符：");charch=getchar();if(ch>='a'&&ch='A'&&ch='0'&&ch

voidmain(){intx,y,z,temp;scanf("%d",&x);scanf("%d",&y);scanf("%d",&z);if(x再问：你的完全正确

#includeintmain(){chara,b;a=getchar();scanf("%c",&b);printf("a=%c\n",a);printf("b=%c\n",b);return0;}

1.floatpi(){floatmin=1;floatpi=0;floatpi_1=0;floati=1;while(min>0.01){pi_1=pi+1/i;if(i>0)

#includevoidmain(){inta,b,c;intd,e,f,sum;printf("请输入三个整数：\n");scanf("%d,%d,%d",&a,&b,&c);//分号放错位置了su

你所写的代码是正确的,想要查看,请用这个：#includeintmain(){charch;scanf("%c",&ch);if(ch>='A'&&ch

不对,实质上这种情况该用char类型,并判断,因为int可输入多位,例如输入11,12,14你这种算法就不能反向输出

////第一个程序#include <stdio.h>int main(){char ch;int count = 0;i

两次调用swap（交换位置）函数就可以,swap函数在谭浩强的C语言上有的.

#include<stdio.h>int main(){int a,b,c,d,t; printf("please enter 

a+b>cabs(a-b)再问：能编个完整的给我吗？谢谢。新手，看不懂啊……不胜感激再答：#includeinta,b,c;scanf("%d,%d,%d",&a,&b,&c);if(a>0&&b>0

#include#includevoidmain(){intnum;printf("input\t:");scanf("%d",&num);printf("%d\t%d\n",num,abs(

我可以给你写出代码,#includeintmain(){inti,j,k,n;scanf("%d",&n);for(i=1;i

第一个#includevoidmain(){chara;scanf("%c",&a);if((a>'a')&&(a

#include#includeintmain(){inta,b,c;floatp,s;scanf("%d%d%d",&a,&b,&c);if(a+b>c&&a+c>b&&b+c>a){p=(a+b+

#includevoidmain(){\x09intyear;\x09printf("请输入年份：");\x09scanf("%d",&year);\x09if((year%4==0&&year/10

#include#definetrue1voidprint(charcType,intiRow,intiColumn,charcMark){inti,j;if(cType=='A'){for(i=0;

#include"stdio.h"voidmain(){charch;scanf("%c",&ch);if(ch>='0'&&ch='a'&&ch='A'&&ch

1:#includeintmain(){inta[10],i,*p,j,temp;for(i=0;i

#includevoidmain(){inta,b,c,d;printf("Pleaseinput3numbers,example,[1,2,3]:\n");scanf("%d,%d,%d",&a,&