cos 3k 1 3π α

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已知α,β∈(π/2,π)且tanα

Ccotβ=tan(3/2π-β)tanα

化简sin^2(α+π)cos(π+α)cot(-α+2π)/tan(π-α)cos^3(-α-π)

sin^2(α+π)cos(π+α)cot(-α+2π)/tan(π-α)cos^3(-α-π)=(-sinα)^2*(-cosα)*cot(-α)/(-tanα)cos^3(-α+π)=(sinα)

化简 [Sin(π+α)\tan(π+α)] ×[ cot(2π-α)\cos(π+α)]×[sec(2π-α)\csc

[Sin(π+α)\tan(π+α)]×[cot(2π-α)\cos(π+α)]×[sec(2π-α)\csc(π-α)]=[(-sinα)\tanα]×[(-cotα)\(-cosα)]×[secα

求证tan(2π-α)sin(-2π-α)cos(6π-α)/cos(α-π)sin(5π-α)=-tanα

tan(2π-α)sin(-2π-α)cos(6π-α)/cos(α-π)sin(5π-α)=(-tana)(-sina)cosa/(-cosa)sina=-tana希望对你有帮助~

已知α为第三象限角,且f(α)=sin(π-α)cos(2π-α)tan(-α+π)/sin(π+α)tan(2π-α)

f(α)=sin(π-α)cos(2π-α)tan(-α+π)/sin(π+α)tan(2π-α)=sinacosa(-tana)/(-sina)(-tana)=-(sinacosatana/sina

化简cos2(π/4-α)-sin2(π/4-α)

cos2(π/4-α)-sin2(π/4-α)=cos(π/2-2α)-sin(π/2-2α)=sin2α-cos2α=√2(√2/2sin2α-cos2α)=√2sin(2α-π/4)根据二倍角公式

化简sin(π/4-α)+cos(π/4+α)

sin(π/4-α)+cos(π/4+α)=sin(π/4-α)+cos[π/2-(π/4-α)]=sin(π/4-α)+sin(π/4-α)=2sin(π/4-α)

已知f(α)=[sin(π-α)cos(2π-α)tan(-α+3π/2)]/[cot(-π-α)sin(-π-α)]

f(a)=-cosasina=-1/5,cosa=-2根号6/5,f(a)=2根号6/5直接代入f(a)=f(-7派/6)=-根号3/2

化简:[sin(π+α)*cos(π-α)*tan(π-α)]/[cos(π/2+α)*tan(3π/2-α)*tan(

[sin(π+α)*cos(π-α)*tan(π-α)]/[cos(π/2+α)*tan(3π/2-α)*tan(α-3π)]=[(-sinα)*(-cosα)*(-tgα)]/[(-sinα)*ct

化简 f(α)=sin(π—α) cos(2π—α)tan(-α+3/2π)/cot(-α-π)sin(-π-α)

-cosα对不对sin(π—α)=sinα,cos(2π—α)=cosα,tan(-α+3/2π)=ctgα,上面就是(cosα)^2;cot(-α-π)=-ctgα,sin(-π-α)=sinα,然

f(α)=[sin(π-α)cos(α-π)tan(-α+π)]/[tan(π+α)cos(3/2π+α)] 化简

f(α)=[sin(π-α)cos(α-π)tan(-α+π)]/[tan(π+α)cos(3/2π+α)]=sinα(-cosα)(-tanα)/(tanαsinα)=cosα再问:cos(3/2π

若f(α)=[sin(π-α)cos(2π-α)tan(-α+π)]/[-tan(-α-π)sin(-π-α)]化简

f(α)=[sin(π-α)cos(2π-α)tan(-α+π)]/[-tan(-α-π)sin(-π-α)]=[sinαcosα(-tanα)]/{tanα[-sin(π+α)}=-sinαcosα

化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}

原式=(-sin³α)cosα(-cosα)/(tan³α)cos²α=sin³α/tan³α=sin³α/(sin³α/cos&

∑'αγαπώ翻译

Σ'αγαπ=我爱你(这是希腊文.)

已知f(α)=sin(π-α)cos(2π-α)tan(π-α)/-tan(-π-α)sin(-π-α),若α是第三象限

f(α)=(sinα*cosα*-tanα)/tan(π+α)*sin(π-α)=(-sinα*cosα*tanα)/tanα*sinα=-cosαcos(α-3π/2)=cos(α-3π/2+2π)

sin(π+α)比上cos(π+α)等于什么

sin(π+α)比上cos(π+α)=tan(π+α)(利用同角关系式)=tanα(利用诱导公式)

化简cos(α-π)cot(5π-α)/tan(2π-α)sin(-2π-α)

cos(α-π)cot(5π-α)/tan(2π-α)sin(-2π-α)=-sinα*(-tanα)/(-tanα)sinα=-(sinα)^2

化简:cos(-π-α)

cos(-π-α)=-cos(-α)=-cosα

sin(π/2+α)·cos(π/2-α)/cos(π+α)+sin(π-α)·cos(π/2+α)/sin(π+α)=

=cosα*sinα/(-cosα)+sinα*(-sinα)/-sinα=-sinα+sinα=0第二题继续啊,先占座(2)sin²40°+sin²50°=sin²40

tan(3/2π-α)=?;cot(-α-π)=?

tan(3/2π-α)=cotα;cot(-α-π)=-cot(π+α)=-cotα.