方程1|x²-1 x²-1|x²
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原方程可化为:1(x−1)(x+2)+1(x+2)(x+5)=2,方程的两边同乘(x-1)(x+2)(x+5),得x+5+x-1=2(x-1)(x+2)(x+5),解得x1=-2+10,x2=-2-1
原分式方程化为:2x+1x(x+1)=56(x+1),方程的两边同乘6x(x+1),得6(2x+1)=5x,解得x=-67.检验:把x=-67代入6x(x+1)≠0,即x=-67是原分式方程的解.则原
x(2x-4)+3x(x-1)=5x(x-3)+82x²-4x+3x²-3x=5x²-15x+88x=8x=1
2x(x-1)-x(3x+2)=-x(x+2)-122x^2-2x-3x^2-2x=-x^2-2x-122x^2-3x^2+x^2-2x-2x+2x=-12-2x+12=0-2(x-6)=0x-6=0
(x²-x+4)x-(x-1)(x²+2)=x+7x³-x²+4x-x³+x²-2x+2=x+72x+2=x+72x-x=7-2x=5
(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=(x/2)*(2/x(x+2))+(2/(x+2)(x+4))+.+2/(x+8)(x+10)=(x/2)*[1/x
x-1%x=19.80.99x=19.8x=19.8/0.99x=20x-40%x=150.6x=15x=15/0.6x=25x+25%x=2.51.25x=2.5x=2.5/1.25x=250%x+
4x+12=8x-112+1=8x-4x13=4xx=13/4
x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)
(X(13-X)(X+(13-X)))/(X+1)=42得分母是X^2(13-X)+(13-X)X分子是(X+1)再得分母X(13-X)(X+1)分子分母抵消的(X+1)X=42得X=6
解题思路:先化简代数式,再把x²-5x=14代入进行计算解题过程:0最终答案:略
1.5X-X=1(1.5-1)X=10.5X=1X=1÷0.5X=2
若方程1-x2=x+m无实数解,则函数y=1-x2与函数y=x+m的图象无交点,在同一坐标系中分别画出函数y=1-x2与函数y=x+m的图象,如图所示:∵函数y=1-x2的导函数y'=-x-x2+1,
方程两边同乘x(x+1)(x+2)(x+3)(x+4),得(x+2)(x+3)(x+4)+x(x+3)(x+4)+x(x+1)(x+4)+x(x+1)(x+2)=421x(x+1)(x+2)(x+3)
即1/x-1/(x+1)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+...+1/(x+9)-1/(x+10)=5/121/x-1/(x+10)=5/12两边乘12x(x+10)1
方程两边同乘(x+1)(x+2)(x+3)(x+4),得(x+3)(x+4)+(x+1)(x+4)+(x+1)(x+2)=(x+1)(x+2)(x+3),∴3x2+15x+18=(x+1)(x+2)(
x(x+1)=42x^2+x-42=0(x-7)(x+6)=0所以x-7=0或x+6=0即x=7,或x=-6
再问:真的很谢谢,懂了
你好,我认真解答了这道题,看最终没有实数解啊.我希望能帮到你