方程1-2 x-1 x2=2x x2

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解方程:X2--1/8(X2+2X)+X2+2X/3(X2--1)=11

设(x²-1)/(x²+2x)=t则8t+3/t=118t²-11t+3=0(8t-3)(t-1)=0解得t=3/8或t=11.t=3/8(x²-1)/(x&#

已知x+1x=2,那么xx2+3x+1-xx2+9x+1的值等于 ___ .

由x+1x=2,两边分别平方得:x+1x=2,原式=1x+1x+3-1x+1x+9=55-1111.故答案为:55-1111.

解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x

后面的x²+11x-708有误吧!再问:没有题目就这样能不能帮我再答:那我就试试:原式为:1/x2+x+1/x2+3x+2+1/x2+5x+6+1/x2+7x+12+1/x2+9x+20=5

Xx2.25%x(1-20%)+x=81440,

Xx2.25%x(1-20%)+x=814400.0225x×0.8+x=814400.018x+x=814401.018x=81440x=80000

解方程 2/(x2-x)+6/(1-x2)=7/(x2+x)

2/(x2-x)+6/(1-x2)=7/(x2+x)2/x(x-1)-6/(x-1)(x+1)=7/x(x+1)[x*(x-1)*(x+1)]*[2/x(x-1)-6/(x-1)(x+1)]=[7/x

计算:(1)x2+9xx2+3x+x2−9x2+6x+9

(1)原式=x(x+9)x(x+3)+(x+3)(x−3)(x+3)2=x+9x+3+x−3x+3=2(x+3)x+3=2;(2)原式=-x−2x−1÷x2−4x−1=-x−2x−1•x−1(x+2)

解方程:7x+2x=0.81;4(x-6)=36;2x+0.2xX2=36

7x+2x=0.819X=0.81X=0.094(x-6)=36;x-6=9x=32x+0.2xX2=362.4x=36x=15

求曲线y=2xx2+1在点(1,1)处的切线方程.

因为y=2xx2+1,所以函数的导数y'=f'(x)=2(x2+1)-2x⋅2x(x2+1)2=2-2x2(x2+1)2,所以f'(1)=2-24=0,即曲线在点(1,1)处的切线斜率k=0,所以曲线

解方程2xx2-1-3x2-3x=2时,若设y=xx2-1,则方程可化为 ___ .

因为3x2-3x=3(x2-1)x,所以原方程可变形为2y-3y=2.故答案为:2y-3y=2.

代数式1x−1+1x+1+2xx2+1+4x3x4+1的化简结果是(  )

1x−1+1x+1+2xx2+1+4x3x4+1=2xx2−1+2xx2+1+4x3x4+1=4x3x4−1+4x3x4+1=8x7x8−1.故选D.

x2+x+1=2/(x2+x)解分式方程

x2+x+1=2/(x2+x)(X²+x)²+(x²+x)-2=0(x²+x+2)(x²+x-1)=0∴x²+x-1=0x=(-1±√5)/

解方程2/x2+x+3/x2-x=4/x2-1

两边乘x(x+1)(x-1)2(x-1)+3(x+1)=4x2x-2+3x+3=4x5x+1=4xx=-1经检验,x=-1时分母x+1=0增根,舍去方程无解

解方程(x2+x)(x2+x-2)=-1

(x²+x)(x²+x-2)=-1把(x²+x)看成整体(x²+x)[(x²+x)-2]=-1运用乘法分配率(x²+x)²-2(x

解方程 x2+x-1/(x2+x)=3/2

x²+x-1/(x²+x)=3/2两边同时乘以(x²+x)得:(x²+x)²-1=3(x²+x)/22(x²+x)²-3

设函数f(x)=2x2+2xx2+1,函数g(x)=ax2+5x-2a.

(1)y=2x2+2xx2+1=2(x2+1)+2x−2x2+1=2+2(x−1)x2+1,令x-1=t,则x=t+1,t∈[-1,0],y=2+2tt2+2t+2,当t=0时,y=2;当t∈[-1,

解方程x-4/x2+x-2=1/(x-1)+(x-6)/(x2-4)

(x-4)/(x²+x-2)=1/(x-1)+(x-6)/(x²-4)(x-4)/(x-1)(x+2)=1/(x-1)+(x-6)/(x-2)(x+2)(x-4)(x-2)=(x-

x2-2x=2x+1解方程

x²-2x=2x+1x²-4x=1x²-4x+4=5(x-2)²=5x-2=±√5x=2±√5

2x+0.2xX2=36用方程怎么解

2x+0.2xX2=362x+0.4x=362.4x=36x=15

7/x2+x+1/x2-1=2/x2-x解方程

把题拍过来帮你解

求出方程的解(x2+1/x2)-2x2/x+1=1

已知方程,然后x=±√7