C 输入正整数输出1 2 3

voidmain(){intn=-1;while(n

//z2.cpp:定义控制台应用程序的入口点.//#include"stdafx.h"#include#includeusingnamespacestd;voidReverse(int&m)//m为4

因为要求从高位输出,第一个循环求出输入得数多少位,并用power保存相关信息（如：输入1,power=1,输入123,power=100,输入1234,power=10000,输入12345,powe

在vc6通过调试运行了,满足你的要求#includevoidmain(){chartra[50][99]={""};inti,j,n;printf("inputn:");scanf("%d",&n);

intmain(intargc,char*argv[]){intinput;intret,num;printf("Inputaint:");scanf("%d",&input);for(;;){num

很简单,用while#includevoidmain(){intn;intm;printf("输入一个数:");scanf("%d",&n);while(n>=1){m=n%10;

#includeintmain(){intn;scanf("%d",&n);do{printf("%d",n%10);}while(n/=10);printf("\n");return0;}

#includeintmain(){intm[10],i,j=0,k;longn;scanf("%ld",&n);k=n;while(k>0){k/=10;j++;}i=j;while(i--){m[

只学循环完全可以办到,关键是要动脑啊#includevoidmain(){\x09intn,m,max,i;\x09max=0;\x09printf("PleaseInputANumber:\n");

#include#includeintmain(){intoldnum;intnewnum=0;inttemp;printf("pleaseinputnumber\n");scanf("%d",&ol

#include#includevoidmain(){intn;printf("pleaseinputn:");scanf("%d",&n);inti,j,sum;for(i=1;i

#includevoidmain(){inti,k,n=0;printf("输入一个数k=");scanf("%d",&k);for(i=1;i

#include <stdio.h>//最大的精度#define MAX_LENGTH 120//计算商int GetFactor(int 

x%10=a1,x/10%10=a2,x/100=a3,a=a1*100+a2*10+a3再答：判断是几位:if(a>100)3if(a>1000)4if(a>10000)5再问：再问：能帮我看一下错

#includemain(){inti,j,N,t,k=0;intscore[100];printf("请输入整数的个数N：\n");scanf("%d",&N);printf("请输入N个整数：\n

#includemain(){intn,sum=0;scanf("%d",&n);for(inti=0;i

修改如下：1.主函数中intcountdigit,digit=2,number中,countdigit重复定义,改为其他变量,比如x2.改为scanf("%d",&number);3.printf("

#include#defineNUM20voidmain(){longn;intdata[NUM]={0},len=0;scanf("%d",&n);do{data[len++]=n%10;n/=10

11、(1)num>0,(2)num=num/10;12、(1)a[i]==n,(2)k=i13、(1)i

作为字符串形式读入比用整形读入好处理,而且数的位数不受限制（整型有数值超界问题）#includevoidmain(){chars[80];//最长80位数字inti,L;printf("pleasei